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Terry holds 12 cards, each of which is red, white, green, or [#permalink]
 11 Sep 2012, 04:52
Question Stats:
67% (02:22) correct
32% (01:09) wrong based on 10 sessions
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions ProjectTerry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white? (1) The probability that the person will select a blue card is 1/3 (2) The probability that the person will select a red card is 1/6 Practice Questions
Question: 39
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
11 Sep 2012, 04:52
SOLUTIONTerry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white?The question asks whether \frac{red+white}{12}<\frac{1}{2} --> is red+white<6. So, basically we need to know whether the number of red or white cards is less than 6. (1) The probability that the person will select a blue card is 1/3 --> the number of blue cards is \frac{1}{3}*12=4. Now, if there is only 1 green card then the number of red or white cards is 12-(4+1)=7 but if there are 3 green cards, then the number of red or white cards is 12-(4+3)=5. Not sufficient. (2) The probability that the person will select a red card is 1/6 --> the number of red cards is \frac{1}{6}*12=2. Not sufficient since we don't know the number of white cards. (1)+(2) We know that there are 4 blue and 2 red cards, but we still don't know how many white cards are there: if there is only one, then the answer is YES but if there are 5 then the answer is NO. Not sufficient. Answer: E.
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
11 Sep 2012, 08:08
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Terry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white? (1) The probability that the person will select a blue card is 1/3 (2) The probability that the person will select a red card is 1/6 Can we determine if there are less than 6 total R or W's in the pack? (1) There is 4 blues so 8 other cards. Therefore R+W <8, if 7 no, if 5, yes. INEFF (2) There is 2 reds so 10 other cards. At least 1B and 1G so there is at most 8 other Whites. So at most 10/12 can be R+W, at least 3 INEFF Together if we say number of R+W = x (i) says 2<x<8, (ii) says 1<x<10 so both together INEFF Therefore E
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
12 Sep 2012, 04:26
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Bunuel wrote: Terry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white?
(1) The probability that the person will select a blue card is 1/3
(2) The probability that the person will select a red card is 1/6
ST 1: Insufficient: P(blue) = 1/3, means there are 4 blue cards. So remaining are 8 cards, but don't know exact distribution. If we consider green =1, P(R+W) >1/2, but if we consider green = 4, P(R+W)<1/2. So insufficient. ST2: Insufficient: P(Red) = 1/6, means there are 2 red cards. So remaining are 10, but don't know exact distribution. If we take white as 5 P(R+W)>1/2, If we take white 2, P(R+W)<1/2. So insufficient. St 1 + St 2: Insufficient: Red =2, Blue = 4, Remaining 6 cards. If we take white 5, P(R+W) >1/2, But if we take White 2 P(R+W) <1/2. So insufficient. Hence Answer E.
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
12 Sep 2012, 13:38
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Terry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white? (1) The probability that the person will select a blue card is 1/3 (2) The probability that the person will select a red card is 1/6 Trick- There is no need to calculate Probability as the question ask about the total no of Red & White cards. Basically the question can be restated as is the number of Red & White cards less than 6-- Red + White <6 Red+ White + Green + Blue = 12 Statement 1 - Probability of Blue = 1/3 = 4 blue cards are there ---->No info is given regarding Red & White----->Insufficient Statement 2 - Probability of Red = 1/6 = 2 red cards are there ---->No info is given regarding White cards----->Insufficient Statement 1 & 2 - Red+ White + Green + Blue = 12 2+ White + Green + 4 = 12 -----> White + Green = 6 Now green can be any number from 0 to 6 i.e. Red + white can be 2,3,4,5,6,7,8----> Insufficient Answer E Hope it helps
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
14 Sep 2012, 06:51
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SOLUTIONTerry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white?The question asks whether \frac{red+white}{12}<\frac{1}{2} --> is red+white<6. So, basically we need to know whether the number of red or white cards is less than 6. (1) The probability that the person will select a blue card is 1/3 --> the number of blue cards is \frac{1}{3}*12=4. Now, if there is only 1 green card then the number of red or white cards is 12-(4+1)=7 but if there are 3 green cards, then the number of red or white cards is 12-(4+3)=5. Not sufficient. (2) The probability that the person will select a red card is 1/6 --> the number of red cards is \frac{1}{6}*12=2. Not sufficient since we don't know the number of white cards. (1)+(2) We know that there are 4 blue and 2 red cards, but we still don't know how many white cards are there: if there is only one, then the answer is YES but if there are 5 then the answer is NO. Not sufficient. Answer: E. Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
02 Feb 2013, 00:32
Bunuel wrote: SOLUTION
Terry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white?
The question asks whether \frac{red+white}{12}<\frac{1}{2} --> is red+white<6. So, basically we need to know whether the number of red or white cards is less than 6.
(1) The probability that the person will select a blue card is 1/3 --> the number of blue cards is \frac{1}{3}*12=4. Now, if there is only 1 green card then the number of red or white cards is 12-(4+1)=7 but if there are 3 green cards, then the number of red or white cards is 12-(4+3)=5. Not sufficient.
(2) The probability that the person will select a red card is 1/6 --> the number of red cards is \frac{1}{6}*12=2. Not sufficient since we don't know the number of white cards.
(1)+(2) We know that there are 4 blue and 2 red cards, but we still don't know how many white cards are there: if there is only one, then the answer is YES but if there are 5 then the answer is NO. Not sufficient.
Answer: E. but don't we know that between red and white there are 6 cards remaining so we get red + white < 6 so it will be a NO in all cases or have I missed something over here?
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Re: Terry holds 12 cards, each of which is red, white, green, or [#permalink]
02 Feb 2013, 00:48
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fozzzy wrote: Bunuel wrote: SOLUTION
Terry holds 12 cards, each of which is red, white, green, or blue. If a person is to select a card randomly from the cards Terry is holding, is the probability less than 1/2 that the card selected will be either red or white?
The question asks whether \frac{red+white}{12}<\frac{1}{2} --> is red+white<6. So, basically we need to know whether the number of red or white cards is less than 6.
(1) The probability that the person will select a blue card is 1/3 --> the number of blue cards is \frac{1}{3}*12=4. Now, if there is only 1 green card then the number of red or white cards is 12-(4+1)=7 but if there are 3 green cards, then the number of red or white cards is 12-(4+3)=5. Not sufficient.
(2) The probability that the person will select a red card is 1/6 --> the number of red cards is \frac{1}{6}*12=2. Not sufficient since we don't know the number of white cards.
(1)+(2) We know that there are 4 blue and 2 red cards, but we still don't know how many white cards are there: if there is only one, then the answer is YES but if there are 5 then the answer is NO. Not sufficient.
Answer: E. but don't we know that between red and white there are 6 cards remaining so we get red + white < 6 so it will be a NO in all cases or have I missed something over here? Total = 12 _________ Blue = 4 Red = 2
White = ?Green = ? If there is 1 white card and 5 green cards, then red+white=3<6. If there are 5 white cards and 1 green card, then red+white=6. Hope it's clear.
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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory
COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!
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Re: Terry holds 12 cards, each of which is red, white, green, or
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02 Feb 2013, 00:48
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