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The 7th digit of (202)^3 is 1) 2 2) 4 3) 8 4) 6

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CEO
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Joined: 15 Aug 2003
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Kudos [?]: 626 [0], given: 781

The 7th digit of (202)^3 is 1) 2 2) 4 3) 8 4) 6  [#permalink] New post 11 Oct 2003, 05:59
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The 7th digit of (202)^3 is

1) 2
2) 4
3) 8
4) 6

show your work please
Intern
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Joined: 03 May 2003
Posts: 30
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: PS : 7th Digit [#permalink] New post 11 Oct 2003, 13:27
praetorian123 wrote:
The 7th digit of (202)^3 is

1) 2
2) 4
3) 8
4) 6

show your work please


Did it the cheap way -
202*202 = 40804
40804 * 202 = 8242408
7th digit is 8

Have another method?
CEO
CEO
Joined: 15 Aug 2003
Posts: 3550
Followers: 55

Kudos [?]: 626 [0], given: 781

Re: PS : 7th Digit [#permalink] New post 13 Oct 2003, 01:26
exy18 wrote:
praetorian123 wrote:
The 7th digit of (202)^3 is

1) 2
2) 4
3) 8
4) 6

show your work please


Did it the cheap way -
202*202 = 40804
40804 * 202 = 8242408
7th digit is 8

Have another method?


correct!

yes, i do :)

(202)^3 ~ (200)^3 = 8000000

Which is a 7 digit number.

Therefore, 7th digit is the last digit.

(202)^1 ends in 2;

(202)^2 ends in 4;

(202)^3 ends in 8;


Thanks
Praetorian
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 [#permalink] New post 13 Oct 2003, 01:52
my approach is quick calculation: 202┬│=(2*101)┬│=8*(100+1)┬│=8*(1 000 000 + 30 000 + 300 + 1)=8*1 030 301=8242408
  [#permalink] 13 Oct 2003, 01:52
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