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# The 7th digit of (202)^3 is 1) 2 2) 4 3) 8 4) 6

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CEO
Joined: 15 Aug 2003
Posts: 3469
Followers: 61

Kudos [?]: 702 [0], given: 781

The 7th digit of (202)^3 is 1) 2 2) 4 3) 8 4) 6  [#permalink]  11 Oct 2003, 04:59
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 0 sessions
The 7th digit of (202)^3 is

1) 2
2) 4
3) 8
4) 6

Intern
Joined: 03 May 2003
Posts: 28
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: PS : 7th Digit [#permalink]  11 Oct 2003, 12:27
praetorian123 wrote:
The 7th digit of (202)^3 is

1) 2
2) 4
3) 8
4) 6

Did it the cheap way -
202*202 = 40804
40804 * 202 = 8242408
7th digit is 8

Have another method?
CEO
Joined: 15 Aug 2003
Posts: 3469
Followers: 61

Kudos [?]: 702 [0], given: 781

Re: PS : 7th Digit [#permalink]  13 Oct 2003, 00:26
exy18 wrote:
praetorian123 wrote:
The 7th digit of (202)^3 is

1) 2
2) 4
3) 8
4) 6

Did it the cheap way -
202*202 = 40804
40804 * 202 = 8242408
7th digit is 8

Have another method?

correct!

yes, i do

(202)^3 ~ (200)^3 = 8000000

Which is a 7 digit number.

Therefore, 7th digit is the last digit.

(202)^1 ends in 2;

(202)^2 ends in 4;

(202)^3 ends in 8;

Thanks
Praetorian
SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 76 [0], given: 0

my approach is quick calculation: 202┬│=(2*101)┬│=8*(100+1)┬│=8*(1 000 000 + 30 000 + 300 + 1)=8*1 030 301=8242408
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