I think it is B.
a = value in 97
b = value in 98
c = value in 99
b = a*(1+x/100)
c = b*(1-y/100) = a*(1+x/100)(1-y/100)
For to be c greater than a, compare c > a
a*(1+x/100)(1-y/100) > a
assuming a <> 0, if we solve the above inequality, we get to condition in B.
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