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The annual rent collected by a corporation from a certain

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Director
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The annual rent collected by a corporation from a certain [#permalink] New post 25 Apr 2006, 11:37
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A
B
C
D
E

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The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?
(1) x > y
(2) xy/100 < x – y

Please explaine your answer.
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 [#permalink] New post 25 Apr 2006, 13:45
The Answer for this should be D.
1997 = A
1998 = A(1+0.0x) = B
1999 = B(1-0.0y) = A(1+0.0x)(1-0.0y) = A(1+10^-2(x-y-xy^-2) = C

Condition 1: As long as x > y Amount in 1999 >1997 - Sufficient
Condition 2: in x-y-xy^-2 is positive then C > A - Sufficient
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 [#permalink] New post 25 Apr 2006, 14:10
I think this would be E.

1) x > y
so let '97 = $100 and x =10 so '98 =$110

and if x>y then y could be 0 , then '99=$110 and $110>$100 (thus 99'>97')

but
if y = 9.9 , x is still greater than y (10>9.9) but '99 now = $99.11
and this makes the rent '98 less than '97

so 1) is Not Sufficient

2) If you plug in numbers it just is another form of saying x has to be greater than y (x>y) which is the same as 1)
so 2) is NS

thus E
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 [#permalink] New post 25 Apr 2006, 16:03
I think it is B.

a = value in 97
b = value in 98
c = value in 99

b = a*(1+x/100)
c = b*(1-y/100) = a*(1+x/100)(1-y/100)

For to be c greater than a, compare c > a
a*(1+x/100)(1-y/100) > a

assuming a <> 0, if we solve the above inequality, we get to condition in B.
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Last edited by giddi77 on 25 Apr 2006, 19:08, edited 1 time in total.
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 [#permalink] New post 25 Apr 2006, 16:21
giddi77 wrote:
I think it is B.

a = value in 97
b = value in 98
c = value in 99

b = a*(1+x/100)
c = b*(1-x/100) = a*(1+x/100)(1-y/100)

For to be c greater than a, compare c > a
a*(1+x/100)(1-y/100) > a

assuming a <> 0, if we solve the above inequality, we get to condition in B.


Another vote for B

question is

A < A(1+x/100)*(1-y/100)
1 < (1+x/100)*(1-y/100)
1 < 1 - y/100 + x/100 - xy/10000
0 < x/100 - y/100 - xy/10000
multiply by 100

x - y - xy/100 > 0
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 [#permalink] New post 26 Apr 2006, 11:00
OA is 'B'.

Great explanations giddi77 and conocieur.

2 Charlie45:
The source is the Internet. These questions very close resemble the real G-questions.
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 [#permalink] New post 26 Apr 2006, 13:05
M8 wrote:
OA is 'B'.
The source is the Internet. These questions very close resemble the real G-questions.


Doesn't matter where you get them from, keep them flowing. Thanks for posting nice Qs :good
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"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

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 [#permalink] New post 27 Apr 2006, 10:07
giddi77 wrote:
M8 wrote:
OA is 'B'.
The source is the Internet. These questions very close resemble the real G-questions.


Doesn't matter where you get them from, keep them flowing. Thanks for posting nice Qs :good


No probs I will continue, but mate why you do not answer on every question I post? As I see you are gini in math.
  [#permalink] 27 Apr 2006, 10:07
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