Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

The annual rent collected by a corporation from a certain [#permalink]
01 Oct 2008, 10:03

00:00

A

B

C

D

E

Difficulty:

5% (low)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 10:32

1) Insufficient

Substitute 20 for x, 19 for y, and 100 for rent in 1997. 1997: 100 1998: 100+100*0.2 = 120 1999: 120-120*0.19 = 120-22.8 = 97.2 which gives an answer "NO' that 1999 rent > 1997 rent

Substitute 20 for x, 1 for y, and 100 for rent in 1997 1997: 100 1998: 100+100*0.2 = 120 1999: 120-120*0.01 = 120-1.2 = 118.8 which gives an answer "YES" that 1999 rent > 1997 rent

2) Insufficient

Substitute 20 for x, 19 for y, and 100 for rent in 1997 20*19/100 < 20-19 380/100 < 1 3.8 < 1 Not true for this condition

Substitiute 20 for x, 1 for y, and 100 for rent in 1997 20*1/100 < 20-1 1/5 < 19 True for this condition

When combining both conditions x>y and xy/100 < x-y, we plug in the number 20 for x, 1 for y, and 100 for rent because these numbers satisfies both conditions as shown above. When x = 20, y = 1, x>y. When x = 20, y = 1, xy/100 < x-y 20*1/100 < 20-1 20/100 < 19 1/5 < 19

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 10:39

vksunder wrote:

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y (2) xy/100 < x – y

Answer is B.

Let rent in 1997 = 1 rent in 1998 = 1+(x/100) rent in 1999 = [1+(x/100)]+[{1+(x/100)}{1-(y/100)}].......coz [a + b% of a] = [1+(x/100)] [1-(y/100)] The question demands: Is [1+(x/100)] [1-(y/100)] > 1 ??

assume this to be true & solve it further: => (100+x)(100-y)> 10000 => 10000 + 100x -100y -xy >10000 => 100x-100y-xy>0 => 100(x-y)>xy => x-y > (xy/100)

This is exactly given by option 2. Therefore, option 2 is sufficient.

x>y i.e. option1 doesnt lead us anywhere. Therefore answer is B.

Last edited by jatinrai on 01 Oct 2008, 11:32, edited 1 time in total.

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 11:15

jatinrai wrote:

vksunder wrote:

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y (2) xy/100 < x – y

Answer is B.

Let rent in 1997 = 1 rent in 1998 = 1+(x/100) rent in 1999 = [1+(x/100)]+[{1+(x/100)}{1+(y/100)}].......coz [a + b% of a] = [1+(x/100)] [1+(y/100)] The question demands: Is [1+(x/100)] [1+(y/100)] > 1 ??

assume this to be true & solve it further: => (100+x)(100-y)> 10000 => 10000 + 100x -100y -xy >10000 => 100x-100y-xy>0 => 100(x-y)>xy => x-y > (xy/100)

This is exactly given by option 2. Therefore, option 2 is sufficient.

x>y i.e. option1 doesnt lead us anywhere. Therefore answer is B.

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 11:32

scthakur wrote:

jatinrai wrote:

vksunder wrote:

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y (2) xy/100 < x – y

Answer is B.

Let rent in 1997 = 1 rent in 1998 = 1+(x/100) rent in 1999 = [1+(x/100)]+[{1+(x/100)}{1+(y/100)}].......coz [a + b% of a] = [1+(x/100)] [1+(y/100)] The question demands: Is [1+(x/100)] [1+(y/100)] > 1 ??

assume this to be true & solve it further: => (100+x)(100-y)> 10000 => 10000 + 100x -100y -xy >10000 => 100x-100y-xy>0 => 100(x-y)>xy => x-y > (xy/100)

This is exactly given by option 2. Therefore, option 2 is sufficient.

x>y i.e. option1 doesnt lead us anywhere. Therefore answer is B.

I think you meant 1-(y/100) here.

Yup. Solved it on paper then copied. Hence, error.

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 19:37

As far as I can understand [1+(x/100)] [1-(y/100)] is diference b/w rent in 1999 and 1998. Y did u consider it >1 ?

jatinrai wrote:

vksunder wrote:

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y (2) xy/100 < x – y

Answer is B.

Let rent in 1997 = 1 rent in 1998 = 1+(x/100) rent in 1999 = [1+(x/100)]+[{1+(x/100)}{1-(y/100)}].......coz [a + b% of a] = [1+(x/100)] [1-(y/100)] The question demands: Is [1+(x/100)] [1-(y/100)] > 1 ?? assume this to be true & solve it further: => (100+x)(100-y)> 10000 => 10000 + 100x -100y -xy >10000 => 100x-100y-xy>0 => 100(x-y)>xy => x-y > (xy/100)

This is exactly given by option 2. Therefore, option 2 is sufficient.

x>y i.e. option1 doesnt lead us anywhere. Therefore answer is B.

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 20:50

vksunder wrote:

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y (2) xy/100 < x – y

B

% increase from 1997 to 1999 P = (1+x/100)(1-y/100) = 1+ x/100-y/100 -xy/(100*100) = 1+ 1/100 ( x-y-xy/100)

from equ 2 xy/100 < x – y --> x-y-xy/100>0

so P>1
_________________

Your attitude determines your altitude Smiling wins more friends than frowning

Re: DS: Annual Rent [#permalink]
01 Oct 2008, 20:53

lylya4 wrote:

x percent more, y percent less

So can we assume x, y >0??

If x,y > 0 then (2) <=> x - y>0 <=> (1)

annual rent in 1997 & 1999 are connected by rent in 1998, so (1) is sufficient hence (2) is sufficient

My answer is D

(1) is not suffcient

for e.g same intial ren 100. increased by 20.01% then rent would be ~120 decreased by 20% 120-24= 96 for e.g same intial ren 100. increased by 40% then rent would be ~140 decreased by 20% 140-28=116
_________________

Your attitude determines your altitude Smiling wins more friends than frowning

gmatclubot

Re: DS: Annual Rent
[#permalink]
01 Oct 2008, 20:53