The annual rent collected by a corporation from a certain : DS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 17 Jan 2017, 00:26

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# The annual rent collected by a corporation from a certain

Author Message
VP
Joined: 26 Apr 2004
Posts: 1218
Location: Taiwan
Followers: 2

Kudos [?]: 606 [0], given: 0

The annual rent collected by a corporation from a certain [#permalink]

### Show Tags

28 Aug 2004, 10:10
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:02) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998.

Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1)x > y

(2) xy/100 < x â€“ y

Intern
Joined: 20 Jul 2004
Posts: 14
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

28 Aug 2004, 14:33
My guess is D..

if x > y then it should be yes

for 2nd statement.. its says the same thing x>y
VP
Joined: 26 Apr 2004
Posts: 1218
Location: Taiwan
Followers: 2

Kudos [?]: 606 [0], given: 0

### Show Tags

29 Aug 2004, 01:43
Hi, all, first of all, let me speak my thought.
In question, we can get each year's annual rent.

1997 1998 1999
M (M+x%M) (M+x%M-[M+x%M]y%)

compare 1997 with 1999:

( M+x%M-[M+x%M]y%) - (M) = M (x-y-xy)%

If x-y-xy >0, then 1999's rent > 1997's rent, or otherwise.

But in (1) and (2), it seems to be not of help to answer the question.
Hence, I choose (E).

Any other ideas?

thank you

Last edited by chunjuwu on 30 Aug 2004, 05:25, edited 1 time in total.
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5062
Location: Singapore
Followers: 30

Kudos [?]: 355 [0], given: 0

### Show Tags

29 Aug 2004, 21:57
Both statements by themselves are sufficient.

If the rent is n --- 1997
then the rent is (100+x)n --- 1998
and the rent is (100-y)(100+x)n = (100^2 + 100x - 100y -xy)n --- 1999

From (1), no matter how big or small the difference is between x and y, (100-y)(100+x) is always positive.
And so (100-y)(100+x)n > n

From (2), xy/100 < x - y
xy < 100x - 100y
also tells us (100^2 + 100x - 100y -xy)n is always positive.

So (100^2 + 100x - 100y -xy)n > n.

Therfore the answer should be (D)
Manager
Joined: 02 Apr 2004
Posts: 224
Location: Utrecht
Followers: 1

Kudos [?]: 21 [0], given: 0

### Show Tags

30 Aug 2004, 04:34
I would choose B

St.1
Consider when x = 20 and y = 10
1997 = 100
1999 = 108

Consider x = 50 and y = 49
1997 = 100
1999 = 76,5

St.2
xy/100 < x - y

x must be greater than y and x = 50 and y = 49 won't work.

My explanation might be not very well, but I think B is the answer.

Correct me if I am wrong.

Regards,

Alex
Senior Manager
Joined: 07 Oct 2003
Posts: 353
Location: Manhattan
Followers: 2

Kudos [?]: 20 [0], given: 0

### Show Tags

30 Aug 2004, 04:49
chunjuwu wrote:
The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998.

Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1)x > y

(2) xy/100 < x â€“ y

I'll go for e.
1) let's say in 97' was 100, let x =10, and y=9.9
98' it was 110, and 99' it was 110(.901)= 99.11
another scenario, x=10, y=5, and 99' > 98
insufficient

2) tells you essentially the same thing, so insufficient
D does not elicit any new info, hence it's E

I think the key here is to test extreme values for % changes
Joined: 31 Dec 1969
Location: Russian Federation
Concentration: Technology, Entrepreneurship
GMAT 1: 710 Q49 V0
GMAT 2: 700 Q V
GMAT 3: 740 Q40 V50
GMAT 4: 700 Q48 V38
GMAT 5: 710 Q45 V41
GMAT 6: 680 Q47 V36
GMAT 7: Q42 V44
GMAT 8: Q42 V44
GMAT 9: 740 Q49 V42
GMAT 10: 740 Q V
GMAT 11: 500 Q47 V33
GMAT 12: 670 Q V
WE: Engineering (Manufacturing)
Followers: 0

Kudos [?]: 199 [0], given: 102132

### Show Tags

30 Aug 2004, 05:03

If X is the amount perceived in 97, income in 99 is equal to X(1+x)(1-y)

id est is (1+x)(1-y) <> 1 <=> 1 +x-y -xy <> 1

1)x>y does not provide the answer

2)xy/100<x-y neither as it is not enough precise xy>xy/100 and x-y >xy/100

1+2) does not change anything
VP
Joined: 26 Apr 2004
Posts: 1218
Location: Taiwan
Followers: 2

Kudos [?]: 606 [0], given: 0

### Show Tags

30 Aug 2004, 05:59
Sorry, let me revise my talk

1997 1998 1999
M (M+x%M) (M+x%M-[M+x%M]y%)

Hence, in 1999, the rent would be
(M+x%M-[M+x%M]y%) = M(1+x%-y%-xy%%)

I think this is a little tricky, it should be xy%% instead of xy%

compare 1999' with 1997'
we get [M(1+x%-y%-xy%%)] - M = M(x%-y%-xy%%) = 1/10000(100x-100y-xy)

if 100x-100y-xy > 0 then 1999' >1997' , or otherwise

in (1) x>y it always positive. so, sufficient.

in (2) xy /100 < x-y => 100x-100y-xy >0 it always positive, so sufficient.

Therefore, I go with (D).
Manager
Joined: 02 Apr 2004
Posts: 224
Location: Utrecht
Followers: 1

Kudos [?]: 21 [0], given: 0

### Show Tags

30 Aug 2004, 06:04
Chunjuwu,

Is there an official answer for this question.
Thanks.

Regards,

Alex
Manager
Joined: 15 Jul 2004
Posts: 75
Location: London
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

31 Aug 2004, 06:42
ywilfred wrote:
Both statements by themselves are sufficient.

If the rent is n --- 1997
then the rent is (100+x)n --- 1998
and the rent is (100-y)(100+x)n = (100^2 + 100x - 100y -xy)n --- 1999

From (1), no matter how big or small the difference is between x and y, (100-y)(100+x) is always positive.
And so (100-y)(100+x)n > n

From (2), xy/100 < x - y
xy < 100x - 100y
also tells us (100^2 + 100x - 100y -xy)n is always positive.

So (100^2 + 100x - 100y -xy)n > n.

Therfore the answer should be (D)

I don't agree with this, I think it should be:

If the rent is n --- 1997
then the rent is (100+x)/100 * n --- 1998
and the rent is [(100-y)/100] * [(100+x)/100] *n --- 1999

[(100-y) /100] * [(100+x) /100] can be >100 or <100. Therefore insufficient

2. is the same as 1, so also insufficient

It would have been D if the rent in 99 were y percent less than that of 97
SVP
Joined: 16 Oct 2003
Posts: 1810
Followers: 4

Kudos [?]: 136 [0], given: 0

### Show Tags

31 Aug 2004, 08:02
I will go with E on this one.

For 1., 2. and comnibed I used the following number.
X = 20
Y = 19
or
X = 20
Y = 10

Whats the OA?
VP
Joined: 26 Apr 2004
Posts: 1218
Location: Taiwan
Followers: 2

Kudos [?]: 606 [0], given: 0

### Show Tags

31 Aug 2004, 08:36
The OA is E,

but I don't think so

thank you.
31 Aug 2004, 08:36
Display posts from previous: Sort by