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do you know one (two) of the angle of parrellogram is 45 deg?
isnt the height always perpendicular to the base? thus forming an isosceles right triangle?
you can draw a parallellogram with two opposit angles 1-1 (or 10-10, 100-100) and rest 179-179 (170-170, 80-80). do you still think that, it is an issoceles triangle if we draw a perpendicular on the base?
only opposit sides are equal not the adjacent sides. we know this facto nly after going through st 1 and 2.
do you know one (two) of the angle of parrellogram is 45 deg?
isnt the height always perpendicular to the base? thus forming an isosceles right triangle?
you are right. the answer is D.
(1) find height and then hypotenuse SUFF
(2) 45 degrees gives an isosles triangle. since we know that area formula is heigh*base and it equals 100. in isosles triangle two sides are equal and hence one of them is sqrt 100. SUFF
the area of a parallelogram is 100. what is the perimeter of the parallelogram ?
1) the base of the parallelogram is 10 2) one of the angles of the parallelogram is 45 degree
CaspAreaGuy wrote:
you are right. the answer is D.
(1) find height and then hypotenuse SUFF
(2) 45 degrees gives an isosles triangle. since we know that area formula is heigh*base and it equals 100. in isosles triangle two sides are equal and hence one of them is sqrt 100. SUFF
good question!
CaspAreaGuy, but what if the base of parallelogram = 100 and height = 1?
Then, the triangle has legs 1:1:sqrt(2) and hence the P = 100*2 + sqrt(2) * 2 = 200 + 2*sqrt(2)?
the area of a parallelogram is 100. what is the perimeter of the parallelogram ?
1) the base of the parallelogram is 10 2) one of the angles of the parallelogram is 45 degree
CaspAreaGuy wrote:
you are right. the answer is D.
(1) find height and then hypotenuse SUFF
(2) 45 degrees gives an isosles triangle. since we know that area formula is heigh*base and it equals 100. in isosles triangle two sides are equal and hence one of them is sqrt 100. SUFF
good question!
CaspAreaGuy, but what if the base of parallelogram = 100 and height = 1? Then, the triangle has legs 1:1:sqrt(2) and hence the P = 100*2 + sqrt(2) * 2 = 200 + 2*sqrt(2)?
but if the base is 100 and height is 1, will it be an isosles triangle? didn't get your point, sorry.
do you know one (two) of the angle of parrellogram is 45 deg?
isnt the height always perpendicular to the base? thus forming an isosceles right triangle?
you can draw a parallellogram with two opposit angles 1-1 (or 10-10, 100-100) and rest 179-179 (170-170, 80-80). do you still think that, it is an issoceles triangle if we draw a perpendicular on the base?
only opposit sides are equal not the adjacent sides. we know this facto nly after going through st 1 and 2.
alright i figured it out.
we can have that figure, or we can have a square. if we have that figure the sides are 10sqrt2 and 10. If we have a square, we have 10 and 10.
so
1) 90 degrees square looks like this
----------
----------
2) 70 degrees looks like this
----------
----------
3) 45 degrees looks like this
----------
----------
4)
35 degrees looks like this
----------
----------
The perimeter could be infinite as the degrees approach 0
This is why you need both
45degrees gives you isosceles both on the base on the height and don't provide enough info in finding the perimeter