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Re: The area of a square garden is A square feet and the perimet [#permalink]
24 Sep 2012, 10:30

1

This post received KUDOS

Expert's post

zz0vlb wrote:

The area of a square garden is A square feet and the perimeter is p feet. If a=2p+9, what is the perimeter of the garden, in feet?

A. 28 B. 36 C. 40 D. 56 E. 64

Let the side of garden be x feet, then: area=a=x^2 and perimeter=p=4x. Given: a=2p+9 --> x^2=2*4x+9 --> solving for x: x=-1 (not a valid solution as x represents the length and therefore must be positive) or x=9 --> perimeter=p=4x=36.

Re: The area of a square garden is A square feet and the perimet [#permalink]
28 Sep 2012, 20:23

This is hovv i solved it

A = a^2 it is a square implies it should be a perfect square

If A = 2P+9, implies a^2 = 2p+9

a^2 = 2(28) + 9 not a perfect square a^2 = 2(36) + 9 perfect square = 80 so a = 9 so permieter = 36 true B a^2 = 2(40) + 9 not a perfect square a^2 = 2(56) + 9 perfect square = 121 so a = 11 if a =11 then permiter =44 condition fails a^2 = 2(64) + 9 not a perfect square

Re: The area of a square garden is A square feet and the perimet [#permalink]
13 Nov 2013, 13:42

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