Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

The arithmetic mean (average) of a set of 10 numbers is 10. Is the median value of the same set also equal to 10?

1) Exactly half of the numbers are less than 10. 2) The mode of the set of numbers is 10.

I'm getting C. Knowing both Stat 1 and Stat 2, we can say that the median value will never be 10.

Median = (5th term + 6th term)/2

Stat 1:
set = 5, 5, 5, 5, 5, 15, 15, 15, 15, 15
In this case median = 10.

set = 4, 4, 4, 4, 9, 15, 15, 15, 15, 15
median is not equal to 10.

Insuff

Stat 2:
set = 10 times 10.
Median = 10

set = 3, 4, 4, 5, 9, 10, 10, 10, 20, 25
median is not equal to 10

Insuff.

Stat 1 & 2:

Since exactly half the values are under 10 then the 5th term has to be less than 10. Since the mode is 10, the 6th term has to be 10.
(10+number less than 10)/2 has to be less than 10.

I get the same - C - using the same rationale as GK_GMAT. What's the OA?

I also got (C) using the same logic as GK_GMAT...(i didn't assume the numbers to be whole numbers since it's not mentioned anywhere)...but the OA is (E)

St1:
The set could be {0,0,0,0,1,10,10,10,10,59}. Mean = 10, Median = 5.5
The set could be {0,0,0,0,0,20,20,20,20,20}. Mean = 10, Median = 10.
Insufficient.

St2:
The set could be {10,10,10,10,10,10,10,10,10,10}. Mode = Mean = Median = 10
The set could be {1,2,3,4,5,6,10,10,10,49}. Mode = 10. Mean = 10. Median = 5.5
Insufficient.

St1 and St2:
The set could be {1,2,3,4,5,10,10,10,10,45}. Mode = Mean = 10. Median = 7.5
The set could eb {0,0,0,0,0,10,10,10,10,60}. Mode = Mean = 10. Median = 5.
Insufficient.

St1: The set could be {0,0,0,0,1,10,10,10,10,59}. Mean = 10, Median = 5.5 The set could be {0,0,0,0,0,20,20,20,20,20}. Mean = 10, Median = 10. Insufficient.

St2: The set could be {10,10,10,10,10,10,10,10,10,10}. Mode = Mean = Median = 10 The set could be {1,2,3,4,5,6,10,10,10,49}. Mode = 10. Mean = 10. Median = 5.5 Insufficient.

St1 and St2: The set could be {1,2,3,4,5,10,10,10,10,45}. Mode = Mean = 10. Median = 7.5 m The set could eb {0,0,0,0,0,10,10,10,10,60}. Mode = Mean = 10. Median = 5. Insufficient.

Ans E

how does it make C insufficient?
If we take both sets together 10 can never be median..question solved.

St1: The set could be {0,0,0,0,1,10,10,10,10,59}. Mean = 10, Median = 5.5 The set could be {0,0,0,0,0,20,20,20,20,20}. Mean = 10, Median = 10. Insufficient.

St2: The set could be {10,10,10,10,10,10,10,10,10,10}. Mode = Mean = Median = 10 The set could be {1,2,3,4,5,6,10,10,10,49}. Mode = 10. Mean = 10. Median = 5.5 Insufficient.

St1 and St2: The set could be {1,2,3,4,5,10,10,10,10,45}. Mode = Mean = 10. Median = 7.5 m The set could eb {0,0,0,0,0,10,10,10,10,60}. Mode = Mean = 10. Median = 5. Insufficient.

Ans E

how does it make C insufficient? If we take both sets together 10 can never be median..question solved.

my bad.... it should be C. I thought the question was asking for the value of the median in which case the answer would be E.

Re: DS : Mean/Median/Mode [#permalink]
11 May 2008, 05:43

vshaunak@gmail.com wrote:

Should be 'E'.

S1 + S2 not suff

case1 - set = {7,8,9,10,10,16} mean=median=mode=10 and 3 elements are smaller than 10. case2- set={1,2,3,4,10,10,10,40} mean=10, mode=10, median=7 and 4 elements and smaller than 10.

Re: DS : Mean/Median/Mode [#permalink]
11 May 2008, 05:52

tarkumar wrote:

vshaunak@gmail.com wrote:

Should be 'E'.

S1 + S2 not suff

case1 - set = {7,8,9,10,10,16} mean=median=mode=10 and 3 elements are smaller than 10. case2- set={1,2,3,4,10,10,10,40} mean=10, mode=10, median=7 and 4 elements and smaller than 10.

St1: The set could be {0,0,0,0,1,10,10,10,10,59}. Mean = 10, Median = 5.5 The set could be {0,0,0,0,0,20,20,20,20,20}. Mean = 10, Median = 10. Insufficient.

St2: The set could be {10,10,10,10,10,10,10,10,10,10}. Mode = Mean = Median = 10 The set could be {1,2,3,4,5,6,10,10,10,49}. Mode = 10. Mean = 10. Median = 5.5 Insufficient.

St1 and St2: The set could be {1,2,3,4,5,10,10,10,10,45}. Mode = Mean = 10. Median = 7.5 The set could eb {0,0,0,0,0,10,10,10,10,60}. Mode = Mean = 10. Median = 5. Insufficient.

Ans E

Quick question.

In you example St1 and St2. Wouldn't the mode be 0 as it's used 5 times and 10 is used 4 times.