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# The ave (arithmetic mean) daily maximum temperature at a

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Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
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Kudos [?]: 19 [0], given: 0

The ave (arithmetic mean) daily maximum temperature at a [#permalink]  30 Oct 2006, 05:09
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
The ave (arithmetic mean) daily maximum temperature at a certain weather station from July12 to July19 was 5 degrees higher than the average daily minimum temperature from July 13 to July 18. What was the maximum temperature on July 12?

(1) The average (arith mean) daily maximum temperature from July 13 to July 18 was 4 degrees less than the maximum temperature on July 19

(2) The average (arith mean) dailiy maximum temperature from July 12 to July 19 was 64 degrees
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Impossible is nothing

Senior Manager
Joined: 01 Sep 2006
Posts: 302
Location: Phoenix, AZ, USA
Followers: 1

Kudos [?]: 15 [0], given: 0

12-19th avg temp = X or sum temp = 8X
13-18 avg temp = Y or sum temp = 6Y

Stem X-Y= 5 (A)

(1) Y = T(Jul19) -4 (B)

Using (A and B) three variables 2 equations INSUFF

(2) X=64 (C)

Using (A and C) three variables 2 equations INSUFF

Using (1) and (2) we can get answer SUFF

In this Q we donot need to solve I have made an attemp any way

Unsing A B C we can derive T on July 12
Y = 59

T(july19) = 59+4 = 63

Sum of Tmep on July 12 and July 19 = 8X - 6Y
Y=59X = 64

July 12 + july 19 = 8*64 - 6*59= 512-354= 158

July 19 = Y + 4 = 59+4=63

July 12 = 158- 63
Manager
Joined: 04 Jan 2006
Posts: 58
Followers: 1

Kudos [?]: 1 [0], given: 0

It should be E.

Damager,
The ave (arithmetic mean) daily maximum temperature at a certain weather station from July12 to July19 was 5 degrees higher than the average daily minimum temperature from July 13 to July 18. What was the maximum temperature on July 12?

Question stem gives ave minimum temp from 13th to 18th.

Stmt 1 says average max temp from 13th to 18th.

So there are 4 variables. Ther are only 3 equations.
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