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The average (arithmetic mean) monthly income of four workers

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The average (arithmetic mean) monthly income of four workers [#permalink]  25 Feb 2013, 09:09
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The average (arithmetic mean) monthly income of four workers is $2,200. After one worker’s income increases by 25 percent the new average income is$2,400. What was the original income of the worker whose monthly income increased?

A. $800 B.$1,200
C. $2,400 D.$3,200
E. It cannot be determined from the information given .
[Reveal] Spoiler: OA

Last edited by Bunuel on 26 Feb 2013, 01:37, edited 2 times in total.
Edited the question.
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Re: The average (arithmetic mean) monthly income of four worker [#permalink]  25 Feb 2013, 09:54
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Expert's post
Let the income of the 3 workers which doesn't change be x1,x2,x3. Let the income s increase by 25%. Thus,

Initially, x1+x2+x3+s= 8800

And later, x1+x2+x3+1.25s = 9600

Subtracting both of them,

0.25s = 800

Thus, s = 3200.

D.
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Re: The average (arithmetic mean) monthly income of four worker [#permalink]  25 Feb 2013, 09:56
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a+b+c+d=4*2.2 => b+c+d=4*2.2-a

1.25a+b+c+d=4*2.4

1.25a+ (4*2.2-a)=4*2.4
0.25a=4*(2.4-2.2)

(1/4)a=4*.02
a=3.2

ans is D
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Re: The average (arithmetic mean) monthly income of four workers [#permalink]  26 Feb 2013, 01:44
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thinktank wrote:
The average (arithmetic mean) monthly income of four workers is $2,200. After one worker’s income increases by 25 percent the new average income is$2,400. What was the original income of the worker whose monthly income increased?

A. $800 B.$1,200
C. $2,400 D.$3,200
E. It cannot be determined from the information given .

Increase in total income was 200*4=$800, we know that this increase was 25% (1/4th) of the workers original income, thus his/her original income was 800*4=$3,200.

Hope it's clear.
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Re: The average (arithmetic mean) monthly income of four workers [#permalink]  09 Apr 2014, 11:26
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Re: The average (arithmetic mean) monthly income of four workers   [#permalink] 09 Apr 2014, 11:26
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