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The average (arithmetic mean) of the 5 positive integers k, [#permalink]
05 Oct 2008, 15:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
k < m < r < s < t, so the median in the following list is r.
r is the greatest possible when k, m, s are the smallest possible i.e. k = 1, m = 2, s = r+1 Note: k cannot be zero because they had mentioned k, m, r, s and t in question as positive integers.
sum = 1 + 2 + r + (r+1) + 40 = 16 x 5 = 80 => r = 18
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16 B. 18 C. 19 D. 20 E. 22
k+m+r+s+t = 80 if t = 40 thus k+m+r+s = 40
k,m,r,s have different values not = 0 and r is in the middle of the values = median
least values of k,m= 1,2
thus s+r = 80 - 43 = 37
r<s thus , s<40
r can only be 18 so that s can be = 19 ( ie slightly bigger)
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16 B. 18 C. 19 D. 20 E. 22
k+m+r+s+t = 80 if t = 40 thus k+m+r+s = 40
k,m,r,s have different values not = 0 and r is in the middle of the values = median
least values of k,m= 1,2
thus s+r = 80 - 43 = 37
r<s thus , s<40
r can only be 18 so that s can be = 19 ( ie slightly bigger)
Let replace r with 19, can you find the other integers?
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16 B. 18 C. 19 D. 20 E. 22
k+m+r+s+t = 80 if t = 40 thus k+m+r+s = 40
k,m,r,s have different values not = 0 and r is in the middle of the values = median
least values of k,m= 1,2
thus s+r = 80 - 43 = 37
r<s thus , s<40
r can only be 18 so that s can be = 19 ( ie slightly bigger)
Let replace r with 19, can you find the other integers?
I am sorry , but i do not get your question, please rephrase