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The average (arithmetic mean) weight of two men is x, which

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The average (arithmetic mean) weight of two men is x, which [#permalink] New post 14 Oct 2005, 08:06
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The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. What is the average weight of all five men in terms of x?
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 [#permalink] New post 14 Oct 2005, 08:27
I think the answer is 7x/10.

(2*x + 3 * x/2) / 5
= ( (4x + 3x)/2)/5

= 7x/10
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 [#permalink] New post 14 Oct 2005, 08:34
Total wt of 2 -> 2x
Total wt of other 3 -> (x/2)*3

Total Avg -> (4x+3x/2)/5 = 7x/10
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 [#permalink] New post 14 Oct 2005, 08:34
sudhagar wrote:
I think the answer is 7x/10.

(2*x + 3 * x/2) / 5
= ( (4x + 3x)/2)/5

= 7x/10


You right. Missed the obvious, as usual :)
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 [#permalink] New post 14 Oct 2005, 09:08
OA is 7X/10. Sud caught it.
  [#permalink] 14 Oct 2005, 09:08
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The average (arithmetic mean) weight of two men is x, which

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