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The average (arithmetic mean) weight of two men is x, which

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14 Oct 2005, 08:06
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The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. What is the average weight of all five men in terms of x?
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14 Oct 2005, 08:27
I think the answer is 7x/10.

(2*x + 3 * x/2) / 5
= ( (4x + 3x)/2)/5

= 7x/10
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14 Oct 2005, 08:34
Total wt of 2 -> 2x
Total wt of other 3 -> (x/2)*3

Total Avg -> (4x+3x/2)/5 = 7x/10
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14 Oct 2005, 08:34
sudhagar wrote:
I think the answer is 7x/10.

(2*x + 3 * x/2) / 5
= ( (4x + 3x)/2)/5

= 7x/10

You right. Missed the obvious, as usual
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14 Oct 2005, 09:08
OA is 7X/10. Sud caught it.
14 Oct 2005, 09:08
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The average (arithmetic mean) weight of two men is x, which

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