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The average distance between the Sun and a certain planet is

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The average distance between the Sun and a certain planet is [#permalink] New post 15 Oct 2012, 03:36
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The average distance between the Sun and a certain planet is approximately 2.3 x 10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometers? (1 kilometer is approximately 3.9 x 10^4 inches.)

(A) 7.1 x 10^8
(B) 5.9 x 10^9
(C) 1.6 x 10^10
(D) 1.6 x 10^11
(E) 5.9 x 10^11

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Re: The average distance between the Sun and a certain planet is [#permalink] New post 15 Oct 2012, 03:36
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The average distance between the Sun and a certain planet is approximately 2.3 x 10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometers? (1 kilometer is approximately 3.9 x 10^4 inches.)

(A) 7.1 x 10^8
(B) 5.9 x 10^9
(C) 1.6 x 10^10
(D) 1.6 x 10^11
(E) 5.9 x 10^11

The distance in kilometers would be: \frac{2.3*10^{14}}{3.9*10^4}\approx{\frac{23*10^{13}}{4*10^4}}\approx{6*10^9}.

Answer: B.
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 15 Oct 2012, 03:42
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Distance between the Sun and a certain planet in Inches = 2.3 x 10^14
1 kilometer = 3.9 x 10^4 inches
Distance between the Sun and a certain planet in Km = (2.3 x 10^14)/ (3.9 x 10^4)
= (23/39) * 10^10
= (230/39) * 10^9
= 5.9 * 10^9

Answer B
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 15 Oct 2012, 04:04
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Good question.

I took 2.3 x 10^14and rounded down to 2*10^14, and took 3.9*10^4 and rounded up to 4*10^4.

Then, I did a unit conversion from Inches to Kilometers: (2*10^14 Inches) * (\frac{1 Kilometer}{(4*10^4 Inches)})

Canceling out, we get \frac{(2*10^14 Inches)}{(4*10^4 Inches)}*1 Kilometer = 0.5*10^10 Kilometer or 5*10^9 Kilometers

Since we rounded to begin with, we have to look for the solution that is both closest to our answer AND makes the most sense. In this case, the answer is
[Reveal] Spoiler:
B, 5.9*10^9 Kilometers.

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Re: The average distance between the Sun and a certain planet is [#permalink] New post 15 Oct 2012, 09:59
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Distance in inches = 2.3 * 10^14
Hence distance in KM = 2.3 * 10^14 / 3.9* 10^4
= 2.3/3.9 * 10^10
=230/39 * 10^9
230/39 is approximately 230+/40
hence approximate distance = 5.9 * 10^9

Ans B

Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

The average distance between the Sun and a certain planet is approximately 2.3 x 10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometers? (1 kilometer is approximately 3.9 x 10^4 inches.)

(A) 7.1 x 10^8
(B) 5.9 x 10^9
(e) 1.6 x 10^10
(0) 1.6 x 10^11
(E) 5.9 x 10^11

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Re: The average distance between the Sun and a certain planet is [#permalink] New post 16 Oct 2012, 02:43
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1 km/3.9 * 10^4 inches = X km /2.3 * 10^14 inches

cross multiply

X = 2.3 * 10^4/ 3.9 * 10^4

now we have to approximate

2.3 * 10 * 10^9 / 4

therefore 23*10^9/4 = 5.6 * 10^9 so which is close to answer B 5.9 * 10^9
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 19 Oct 2012, 03:56
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SOLUTION

The average distance between the Sun and a certain planet is approximately 2.3 x 10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometers? (1 kilometer is approximately 3.9 x 10^4 inches.)

(A) 7.1 x 10^8
(B) 5.9 x 10^9
(C) 1.6 x 10^10
(D) 1.6 x 10^11
(E) 5.9 x 10^11

The distance in kilometers would be: \frac{2.3*10^{14}}{3.9*10^4}\approx{\frac{23*10^{13}}{4*10^4}}\approx{6*10^9}.

Answer: B.

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Re: The average distance between the Sun and a certain planet is [#permalink] New post 22 Oct 2012, 08:04
Bro Bunuel, I wonder who you are and BB also declared you as the mystery man.. :) but you are doing an awesome job out here! thank you for all your help.
My Question is

what if 6.1 x 10^9 is also one of the answer choices? what will your approach be in this case?
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 23 Oct 2012, 04:46
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sachindia wrote:
My Question is

what if 6.1 x 10^9 is also one of the answer choices? what will your approach be in this case?


I wouldn't expect such option to be thrown by the GMAC, but in this case the answer still would be the same:

\frac{2.3*10^{14}}{3.9*10^4}={\frac{23*10^{13}}{3.9*10^4}}={\frac{23}{3.9}*10^9}.

Now, since \frac{23}{3.9} is less than 6 (3.9*6=23.4), then 5.9 x 10^9 would be the closest answer choice than 6.1 x 10^9.

Hope it's clear.
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 19 Dec 2012, 02:49
=\frac{2.3 x 10^{14}}{3.9 x 10^{4}}=\frac{23 x 10^{9}}{4}~5.7x10^9

Answer: B
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 29 Jun 2014, 06:58
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Re: The average distance between the Sun and a certain planet is [#permalink] New post 10 Jul 2014, 01:27
Just looking at the options, A, C & D can be directly ignored as 230/39 would never be in 1's or 7's (0 of 230 adopted :))

After adjusting powers of 10, Answer = B

5.9 * 10^9
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Re: The average distance between the Sun and a certain planet is   [#permalink] 10 Jul 2014, 01:27
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