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The average of 5 distinct single digit integers is 5. If two

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The average of 5 distinct single digit integers is 5. If two [#permalink]

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18 Nov 2005, 16:33
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The average of 5 distinct single digit integers is 5. If two of the integers are discarded, the new average is 4. What is the largest of the 5 integers?

(1) Exactly 3 of the integers are consecutive primes.

(2) The smallest integer is 3.

This is a Data Sufficiency Question.
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18 Nov 2005, 16:44
B.

single digit integer..guess it can be even -ve integers..?

a+b+c+d+e = 25

a+b+c = 12
therefore, d+e=13

(1)
case1:
2+3+7 = 12
4 + 9 = 13
primes: 2,3,7
highest digit: 9

case2:
3+4+5=12
6+7=13
highest digit: 7

INSUFFICIENT

(2) the only conbination that fits is:
3,4,5,6,7
sufficient
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18 Nov 2005, 19:51
duttsit wrote:
B.

primes: 2,3,7

This list is not of consecutive primes

2 3 5
or
3 5 7
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18 Nov 2005, 20:28
I`d say D.

1. only 3,4,5,6,7 works so suff.
2. only 3.4.5.6.7 works so suff.

This problem twisted my mind for a few minutes
Director
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19 Nov 2005, 02:42
I choose D!

From 1, the only disticnt numbers that satisfy the constraints are 3, 4, 5,6, 7
From 2, again 3, 4, 5, 6, 7 is the only set that satisfies.
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Cheers, Rahul.

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19 Nov 2005, 03:31
I agree with Duttsit the ans should be B) For statement A) one option is 2,3,5,7,8 where the average is 5 when.We remove 5 and 8 the average of 2,3,7 is 4. The other option is 2,3,4,5,6 AND the biggest number can not be determined
So B)
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19 Nov 2005, 03:48
BG wrote:
I agree with Duttsit the ans should be B) For statement A) one option is 2,3,5,7,8 where the average is 5 when.We remove 5 and 8 the average of 2,3,7 is 4. The other option is 2,3,4,5,6 AND the biggest number can not be determined
So B)

2,3,5,7,8 series is not possible as stmt 1 says exactly 3 integers are consecutive primes!
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Cheers, Rahul.

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