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The average of 5 distinct single digit integers is 5. If two [#permalink]
18 Nov 2005, 15:33

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A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

100% (00:00) correct
0% (00:00) wrong based on 1 sessions

The average of 5 distinct single digit integers is 5. If two of the integers are discarded, the new average is 4. What is the largest of the 5 integers?

(1) Exactly 3 of the integers are consecutive primes.

From 1, the only disticnt numbers that satisfy the constraints are 3, 4, 5,6, 7
From 2, again 3, 4, 5, 6, 7 is the only set that satisfies. _________________

I agree with Duttsit the ans should be B) For statement A) one option is 2,3,5,7,8 where the average is 5 when.We remove 5 and 8 the average of 2,3,7 is 4. The other option is 2,3,4,5,6 AND the biggest number can not be determined
So B)

I agree with Duttsit the ans should be B) For statement A) one option is 2,3,5,7,8 where the average is 5 when.We remove 5 and 8 the average of 2,3,7 is 4. The other option is 2,3,4,5,6 AND the biggest number can not be determined So B)

2,3,5,7,8 series is not possible as stmt 1 says exactly 3 integers are consecutive primes! _________________

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...