**Quote:**

Sorry I am changing my question from 20 to 21.

11...........................21.....................................32

Place 21 in between and sub. (21-1)/2 and add the same.It will give u the extremes.

They are 11 and 32.

Be careful..

the way to find the extremes described here is not accurate. In order to find the extrems for

consecutive integers, you must know the

average and

the number of integers. (Both of which were given in the original problem you posted).

If the number of consecutive integers is

even then the average will not be an integer. It would be a number with decimal.

For example: average of 2,3,4, 5 = (2+5) / 2 = 3.5

If the number of consecutive integers is

oddthen only the average will be an integer.

for eaxmple, the average of 2, ,3 ,4 is = middle number 3

In the above calculation you meant that 21 is average and 11 and 32 are extremes. However, the average of consecutive integers from 11 to 32 is (11+32)/2 = 43/2 = 21.5

So the point is the method to find the extreme is not accurate.

We must know the number of consecutive integers we are talking about.