The base of a hemisphere is inscribed in one face of a cube

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The base of a hemisphere is inscribed in one face of a cube [#permalink]

10 Jun 2012, 17:43

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The base of a hemisphere is inscribed in one face of a cube and the entire hemisphere in contained within the volume of the cube. What is the ratio of the radius of the hemisphere to the length of a side of the cube?

A. \sqrt{2}:P
B. 1:2
C. 2:P
D. 1:\sqrt{2}
E. 2:1

here i found that logically D=S or 2r=S SO r/s= 1/2 ....is my reason correct?

[Reveal] Spoiler: OA

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Last edited by Bunuel on 10 Jun 2012, 22:12, edited 2 times in total.

Edited the question.

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Re: hemisphere inscribed in a circle [#permalink]

10 Jun 2012, 19:43

Your reasoning is correct.

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Re: hemisphere inscribed in a circle [#permalink]

10 Jun 2012, 19:56

Also, the whole cube/hemisphere is a bit of a misnomer. The situation really is just a circle inscribed in a square. Once you draw that, it's easy to get B
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Re: The base of a hemisphere is inscribed in one face of a cube [#permalink]

11 Jun 2012, 21:01

alchemist009 wrote:

Check out Brian's video on 'circle in a square' and 'square in a circle'.
http://www.veritasprep.com/blog/2011/06 ... in-shapes/
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Re: The base of a hemisphere is inscribed in one face of a cube [#permalink] 11 Jun 2012, 21:01

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The base of a hemisphere is inscribed in one face of a cube

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