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The Binary Ice Cream Shoppe sells two flavors, vanilla and

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Senior Manager
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The Binary Ice Cream Shoppe sells two flavors, vanilla and [#permalink] New post 23 Oct 2005, 18:57
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A
B
C
D
E

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100% (01:02) correct 0% (00:00) wrong based on 0 sessions
The Binary Ice Cream Shoppe sells two flavors, vanilla and chocolate. On friday, the ratio of vanilla cones sold to chocolate cones sold was 2 to 3. If the store had sold 4 more vanilla cones, the ratio of vanilla cones sold to chocolate cones sold would have been 3 to 4. How many vanilla cones did the store sell on Friday?

a) 32
b) 35
c) 42
d) 48
E) 54
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 [#permalink] New post 23 Oct 2005, 21:38
Jainvineet: You are correct. OA is A.

Could you please explain your method?
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 [#permalink] New post 23 Oct 2005, 21:47
sudhagar wrote:
Jainvineet: You are correct. OA is A.

Could you please explain your method?


Vanilla/Choc = 2/3 => 3V=2C
If number of vanilla sold is 4 more, the ratio would be 3/4 so we get V+4/C=3/4 => 4V + 16 = 3C.

Solving for V would give the answer.
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Re: PS: Ice Cream [#permalink] New post 23 Oct 2005, 22:28
sudhagar wrote:
The Binary Ice Cream Shoppe sells two flavors, vanilla and chocolate. On friday, the ratio of vanilla cones sold to chocolate cones sold was 2 to 3. If the store had sold 4 more vanilla cones, the ratio of vanilla cones sold to chocolate cones sold would have been 3 to 4. How many vanilla cones did the store sell on Friday?

a) 32
b) 35
c) 42
d) 48
E) 54


V/C=2/3

3V=2C, V = 2/3C

If the store had sold 4 more vanilla cones, the ratio would be 3/4.

So (V+4)/C = 3/4, substitue V = 2/3C into the equation, I get C = 48, V = 32.

A is my answer
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Re: PS: Ice Cream [#permalink] New post 23 Oct 2005, 23:46
V:C = 2:3 =>3V=2c or V = 2c/3 -> Equn 1
(V+4):c = 3:4 => 4v + 16 = 3c -> Equn 2
Solving equn 1 and 2 we get C=48 and V=32.

Hence A.
Re: PS: Ice Cream   [#permalink] 23 Oct 2005, 23:46
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