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The circumference of the front wheel of a cart is 30 ft long [#permalink]
 19 Feb 2010, 13:43
Question Stats:
70% (02:26) correct
29% (02:33) wrong based on 2 sessions
The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel? A. 20 ft B. 25 ft C. 750 ft D. 900 ft E. 1000 ft
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Last edited by Bunuel on 16 Oct 2012, 06:09, edited 1 time in total.
Edited the question and added the OA.
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Re: The circumference of the front wheel [#permalink]
19 Feb 2010, 13:54
AtifS wrote: The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel?
A. 20 ft
B. 25 ft
C. 750 ft
D. 900 ft
E. 1000 ft
Any thoughts guys?
@Moderators, please! MERGE IT IF ALREADY POSTED. Answer is D. 900/36 ~ 25 (backwheel revolution) = 900/30 ~ 30 front wheel revolution
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Re: The circumference of the front wheel [#permalink]
19 Feb 2010, 13:56
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- for one full revolutions of rear wheel, front wheel would revolve 1 + 1/5 revolutions(36(rear wheel) = 30(front wheel) + 30/5(additional distance travelled by front wheel after it completed ONE FULL revolution))
- so event 5 revolutions of rear wheel will have 6 revolutions of front wheel.
- so 25 revolutions of rear wheel will have 30 revolutions of front wheel(5 more than the rear wheel as asked)
= 25 * 36 = 900
D
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Re: The circumference of the front wheel [#permalink]
19 Feb 2010, 14:11
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Plug in the options.
A and B are ruled out because they are less for 5 revolutions.
Go to C, is 750/30 - 750/36 = 5 ? No.
Go to D, is 900/30 - 900/36 = 5 ? Yes!
D it is.
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Re: The circumference of the front wheel [#permalink]
20 Feb 2010, 00:14
Guys! thank you for your valuable explanation. I t really made easy to understand the question. Kudos
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Re: The circumference of the front wheel [#permalink]
16 Oct 2012, 01:22
C1=30 ft, C2=36 ft
If Rotation1=x, d(distance)=Cx
30(x+5)=36x, x=25, d=30(25+5)=30x30=900
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Re: The circumference of the front wheel
[#permalink]
16 Oct 2012, 01:22
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