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The combined area of the two black squares is equal to 1000

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The combined area of the two black squares is equal to 1000 [#permalink] New post 07 Feb 2012, 16:34
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

80% (03:41) correct 19% (02:11) wrong based on 41 sessions
Attachment:
Square.PNG
Square.PNG [ 1.52 KiB | Viewed 1256 times ]
The combined area of the two black squares is equal to 1000 square units. A side of the larger black square is 8 units longer than a side of the smaller black square. What is the combined area of the two white rectangles in square units?

(A) 928
(B) 936
(C) 948
(D) 968
(E) 972

[Reveal] Spoiler:
Guys this is how I am trying to solve this:

Let

Side of smaller square be x
Side of larger square will be x+8

Area of smaller square x^2
Area of larger square (x+8)^2

So the sum of the areas = 1000 which brings me to the equation x^2+8x-468 . I don't think we an simplify this equation any further, well I can't and therefore need help.
[Reveal] Spoiler: OA

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Re: Area of Square [#permalink] New post 07 Feb 2012, 16:45
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Attachment:
Square.PNG
Square.PNG [ 1.52 KiB | Viewed 1252 times ]
The combined area of the two black squares is equal to 1000 square units. A side of the larger black square is 8 units longer than a side of the smaller black square. What is the combined area of the two white rectangles in square units?

(A) 928
(B) 936
(C) 948
(D) 968
(E) 972

I guess the black squares are the red squares on the diagram.

The length of a smaller square - x;
The length of a larger square - x+8;

The area of entire square - x^2+(x+8)^2=1000 --> 2x^2+16x=936;
The combined area of the two white rectangles - x(x+8)+x(x+8)=2x^2+16x --> look up: 2x^2+16x=936.

Answer: B.
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Re: The combined area of the two black squares is equal to 1000 [#permalink] New post 29 May 2013, 08:25
enigma123 wrote:
Attachment:
Square.PNG
The combined area of the two black squares is equal to 1000 square units. A side of the larger black square is 8 units longer than a side of the smaller black square. What is the combined area of the two white rectangles in square units?

(A) 928
(B) 936
(C) 948
(D) 968
(E) 972

[Reveal] Spoiler:
Guys this is how I am trying to solve this:

Let

Side of smaller square be x
Side of larger square will be x+8

Area of smaller square x^2
Area of larger square (x+8)^2

So the sum of the areas = 1000 which brings me to the equation x^2+8x-468 . I don't think we an simplify this equation any further, well I can't and therefore need help.

Let smaller square be of side x then bigger square has a side of x+8
(x)^2 +(x+8)^2=1000
2x^2+8x-468=1000
(x+26)(x-18)=0
x=18
Now,the entire figure is a square of side 18+26=44
Total are=44^2=1936
White are=total area-coloured area=1936-1000=936
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Re: The combined area of the two black squares is equal to 1000 [#permalink] New post 25 May 2013, 03:57
Expert's post
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Re: The combined area of the two black squares is equal to 1000 [#permalink] New post 27 May 2013, 22:21
enigma123 wrote:
Attachment:
Square.PNG
The combined area of the two black squares is equal to 1000 square units. A side of the larger black square is 8 units longer than a side of the smaller black square. What is the combined area of the two white rectangles in square units?

(A) 928
(B) 936
(C) 948
(D) 968
(E) 972


Let

Side of smaller square be x
Side of larger square will be x+8

Area of smaller square x^2
Area of larger square (x+8)^2

So the sum of the areas = 1000 which brings me to the equation x^2+8x-468 . I don't think we an simplify this equation any further, well I can't and therefore need help.



X^2 +26x- 18x-468=0 ie X=18 and X= -26.

Discard negative value thus X=18.

Hope it helps...
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Re: The combined area of the two black squares is equal to 1000 [#permalink] New post 29 May 2013, 18:24
Let a be side of big square
b be side of small square
given a*a +b*b =1000
and a=8+b

so (8+b)^2+b^2=1000
on solving b = 18 and a=26

need to find total area of two rectangles given
we get 44^2-1000 = 936


Sol:B
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Re: The combined area of the two black squares is equal to 1000 [#permalink] New post 29 May 2013, 20:32
sum of area of black squares(1000) + sum of area of white rectangles(X) = area of the larger square (Y)

From the options, X is an integer, hence Y (= X + 1000) is an integer too.

As Y is a square number, From the properties of square numbers, Y can only end with 0,1,4,6,9 or 25.

From the given options, only B (ending 6) is a possible solution, as +1000 doesn't change unit digit value.
Number ending 2 or 8 + 1000 (as in all other options) can never be a square number.

Besides, all of the above ways are equally correct.
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Re: The combined area of the two black squares is equal to 1000   [#permalink] 29 May 2013, 20:32
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