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The concentration of a certain chemical in a full water tank [#permalink]
16 Nov 2005, 17:58
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Difficulty:
35% (medium)
Question Stats:
75% (02:48) correct
25% (02:37) wrong based on 176 sessions
The concentration of a certain chemical in a full water tank depends on the depth of the water. At a depth that is x feet below the top of the tank, the concentration is \(3 + \frac{4}{\sqrt{5-x}}\) parts per million, where 0 < x < 4. To the nearest 0.1 foot, at what depth is the concentration equal to 6 parts per million?
(A) 2.4 ft (B) 2.5 ft (C) 2.8 ft (D) 3.0 ft (E) 3.2 ft
I was going to go with 3.0...but then the question says witin 0.1 feet...and with 3.0..we get within 0.2 feet...so I would have just picked 3.2 at that point....
Re: Problem Solving Proportion [#permalink]
16 Nov 2005, 18:49
joemama142000 wrote:
The concentration of a certain chemical in a full water tank depends on the depth of the water. At a depth that is x feet below the top of the tank, the concentration is 3 + 4/sqrt(5-x) parts per million, where 0< x < 4. To the nearest 0.1 foot, at what depth is the concentration equal to 6 parts per million?
I was going to go with 3.0...but then the question says witin 0.1 feet...and with 3.0..we get within 0.2 feet...so I would have just picked 3.2 at that point.... anyway 4/sqrt(5-x)=3 16/(5-x)=9 16=45-9x solve for X...
not yet...its raining here...and I want to go to the gym
to go or not to go to gym is the question...what would GSR do?hmm
gsr wrote:
fresinha12 wrote:
I was going to go with 3.0...but then the question says witin 0.1 feet...and with 3.0..we get within 0.2 feet...so I would have just picked 3.2 at that point.... anyway 4/sqrt(5-x)=3 16/(5-x)=9 16=45-9x solve for X...
Re: The concentration of a certain chemical in a full water tank [#permalink]
01 Mar 2014, 12:11
My brain is cloudy, going to gym to clear it up....but how did you guys know to set the equation equal to 6? Once we get to the equation the math is easy but I did not know where to begin. Can someone explain? _________________
Re: The concentration of a certain chemical in a full water tank [#permalink]
02 Mar 2014, 03:40
1
This post received KUDOS
Expert's post
PeterHAllen wrote:
The concentration of a certain chemical in a full water tank depends on the depth of the water. At a depth that is x feet below the top of the tank, the concentration is \(3 + \frac{4}{\sqrt{5-x}}\) parts per million, where 0 < x < 4. To the nearest 0.1 foot, at what depth is the concentration equal to 6 parts per million?
(A) 2.4 ft (B) 2.5 ft (C) 2.8 ft (D) 3.0 ft (E) 3.2 ft
My brain is cloudy, going to gym to clear it up....but how did you guys know to set the equation equal to 6? Once we get to the equation the math is easy but I did not know where to begin. Can someone explain?
Given: at a depth that is x feet below the top of the tank, the concentration is \(3 + \frac{4}{\sqrt{5-x}}\) parts per million.
Question: at what depth, for which x, is the concentration equal to 6 parts per million? So, for which x, is \(3 + \frac{4}{\sqrt{5-x}}\) equal to 6?
Re: The concentration of a certain chemical in a full water tank [#permalink]
29 Sep 2015, 02:32
I've been trying to wrap my head around how to set up that equation, but am not able to. Could someone please help me out with why I should be equating 6ppm with the concentration at x feet?
gmatclubot
Re: The concentration of a certain chemical in a full water tank
[#permalink]
29 Sep 2015, 02:32
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