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The cost of sending a package is T cents for the first 1/4 kilogram an

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Bunuel
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The cost of sending a package is T cents for the first 1/4 kilogram an [#permalink] New post   09 Jan 2021, 01:18
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The cost of sending a package is T cents for the first 1/4 kilogram and T/5 cents for each additional 1/4 kilogram or fraction thereof. What is the cost, in cents, to send a P kilogram package at this rate, where P is an integer greater than 1.

A. \(\frac{PT}{20}\)

B. \(\frac{PT-1}{20}\)

C. \((\frac{P}{4}+1)T\)

D. \(\frac{(16P-1)T}{20}\)

E. \(\frac{4(P+1)T}{5}\)
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Re: The cost of sending a package is T cents for the first 1/4 kilogram an [#permalink] New post   09 Jan 2021, 02:09
Bunuel wrote:
The cost of sending a package is T cents for the first 1/4 kilogram and T/5 cents for each additional 1/4 kilogram or fraction thereof. What is the cost, in cents, to send a P kilogram package at this rate, where P is an integer greater than 1.

A. \(\frac{PT}{20}\)

B. \(\frac{PT-1}{20}\)

C. \((\frac{P}{4}+1)T\)

D. \(\frac{(16P-1)T}{20}\)

E. \(\frac{4(P+1)T}{5}\)


for simplicity, let's say price of delivery is 4T/5 for every kilogram of delivery.
the cost is
T + \(\frac{4T}{5}\)*\(\frac{P-1}{4}\) =
= T + \(\frac{4T}{5}\)*\(\frac{(4P - 1)}{4}\) =
= T + \(\frac{(4P-1)*T}{5}\)
= T*(\(\frac{(4P-1)}{5}\) + 1)
= T*(\(\frac{(4P+4)}{5}\))

= 4T*(\(\frac{(P+1)}{5}\))
= \(\frac{4(P+1)T}{5}\)
The answer is E
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The cost of sending a package is T cents for the first 1/4 kilogram an [#permalink] New post   09 Jan 2021, 03:41
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SOLUTION:

Number of quarter kilograms in P kg=4P,
Thus,the cost of sending a P kilogram package is:

T + (T/5)(4P - 1) = 5T/5 + (4PT - T)/5
= (4PT + 4T)/5 = 4T(P + 1)/5 OPTION(E)

Hope this helps :thumbsup:
Devmitra Sen(Math)
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Re: The cost of sending a package is T cents for the first 1/4 kilogram an [#permalink] New post   09 Jan 2021, 04:07
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The cost of sending a package is T cents for the first 1/4 kilogram and T/5 cents for each additional 1/4 kilogram or fraction thereof. What is the cost, in cents, to send a P kilogram package at this rate, where P is an integer greater than 1.

For 1/4 kg -> T
for 1/4 +1/4 kg -> T + T/5
for 1/4 +1/4 +1/4 kg -> T+ T/5 + T/5,

there is a trend of 3 times 1/4 kg needs T + (3-1) times T/5 cents
So, 4P/4 kg = P kg -> T+ (4P-1)*T/5 = 4 (P+1)T/5

So, I think E. :)
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Re: The cost of sending a package is T cents for the first 1/4 kilogram an [#permalink] New post   10 Sep 2022, 09:12
CrackverbalGMAT wrote:
SOLUTION:

Number of quarter kilograms in P kg=4P,
Thus,the cost of sending a P kilogram package is:

T + (T/5)(4P - 1) = 5T/5 + (4PT - T)/5
= (4PT + 4T)/5 = 4T(P + 1)/5 OPTION(E)

Hope this helps :thumbsup:
Devmitra Sen(Math)



Can anyone solve this by using numbers and trying to match them with variables pls. I tried however answer is not matching with either
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Re: The cost of sending a package is T cents for the first 1/4 kilogram an [#permalink]
10 Sep 2022, 09:12
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