Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

The distance from X to Y is 20 miles, and the distance from [#permalink]
03 May 2003, 16:49

00:00

A

B

C

D

E

Difficulty:

25% (medium)

Question Stats:

86% (01:51) correct
14% (00:47) wrong based on 21 sessions

The distance from X to Y is 20 miles, and the distance from X to Z is 12 miles. If d is the distance, in miles, between Y and Z, then d is indicated by:

A. 8 ≤ d ≤ 20 B. 8 ≤ d ≤ 32 C. 12 ≤ d ≤ 20 D. 12 ≤ d ≤ 32 E. 20 ≤ d ≤ 32

The distance from X to Y is 20 miles, and the distance from [#permalink]
09 Oct 2008, 05:08

The distance from X to Y is 20 miles, and the distance from X to Z is 12 miles. If d is the distance, in miles, between Y and Z, then d is indicated by:

A. 8 ≤ d ≤ 20 B. 8≤ d ≤ 32 C. 12≤d ≤ 20 D. 12≤d ≤ 32 E. 20 ≤d ≤32 _________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Re: PS: Distance Trouble [#permalink]
10 Oct 2008, 04:00

amitdgr wrote:

The distance from X to Y is 20 miles, and the distance from X to Z is 12 miles. If d is the distance, in miles, between Y and Z, then d is indicated by:

A. 8 ≤ d ≤ 20 B. 8≤ d ≤ 32 C. 12≤d ≤ 20 D. 12≤d ≤ 32 E. 20 ≤d ≤32

Re: PS: Distance Trouble [#permalink]
01 Nov 2008, 12:53

Another approach: Look at three points as forming a triangle. Third side of triangle will be >= difference between the two sides and <= sum of two sides.

Re: PS: Distance Trouble [#permalink]
02 Nov 2008, 22:35

scthakur wrote:

Another approach: Look at three points as forming a triangle. Third side of triangle will be >= difference between the two sides and <=sum of two sides.

Hence, 20-8 <= d <= 20+12.

Caution ! Third side of the triangle will be greater than the difference between the two sides and less than the sum of two sides. (Not >= or <=) In this case, it is not mentioned that the 3 points are not on the same line. Hence the '=' scenario comes into play.

Re: PS: Distance Trouble [#permalink]
02 Nov 2008, 22:43

kandyhot27 wrote:

scthakur wrote:

Another approach: Look at three points as forming a triangle. Third side of triangle will be >= difference between the two sides and <=sum of two sides.

Hence, 20-8 <= d <= 20+12.

Caution ! Third side of the triangle will be greater than the difference between the two sides and less than the sum of two sides. (Not >= or <=) In this case, it is not mentioned that the 3 points are not on the same line. Hence the '=' scenario comes into play.

Good point. Thanks for pointing out. When the area of triangle becomes zero, all the three vertices lie on a straight line and then only equality sign will hold true.

gmatclubot

Re: PS: Distance Trouble
[#permalink]
02 Nov 2008, 22:43

I couldn’t help myself but stay impressed. young leader who can now basically speak Chinese and handle things alone (I’m Korean Canadian by the way, so...