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The equation (M+6)/36=(p-7)/21 relates two temperature

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The equation (M+6)/36=(p-7)/21 relates two temperature [#permalink] New post 19 Oct 2006, 10:32
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The equation (M+6)/36=(p-7)/21 relates two temperature scales, where M is the number of degrees on one scale and P is the number of degrees on the other scale. Which of the following equations can be used to convert temperatures from the P scale to the M scale?

A) M=(7/12)P+13
B) M=(7/12)P+21
C) M=(7/12)P-12
D) M=(7/12)P-13
E) M=(7/12)P-18
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 [#permalink] New post 19 Oct 2006, 11:53
I don't find any option to be correct :(
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 [#permalink] New post 19 Oct 2006, 13:11
Me neither. B is the closest of the options.
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 [#permalink] New post 19 Oct 2006, 13:14
Neither do I....plugging numbers into the equations doesn't allow any of them to match up
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 [#permalink] New post 19 Oct 2006, 13:28
I could not find the value either....

Maybe somebody can explain? There may be a mistake....
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 [#permalink] New post 19 Oct 2006, 13:40
(E) if the typo 7/12 is adapted to 12/7. :)

(M+6)/36=(p-7)/21
<=> M+6 = 36*(p-7)/21
<=> M = 12/7*p - 18
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 [#permalink] New post 19 Oct 2006, 13:50
Fig wrote:
(E) if the typo 7/12 is adapted to 12/7. :)

(M+6)/36=(p-7)/21
<=> M+6 = 36*(p-7)/21
<=> M = 12/7*p - 18


There is something with my algebra.... i cannot get -18....
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 [#permalink] New post 19 Oct 2006, 13:52
SimaQ wrote:
Fig wrote:
(E) if the typo 7/12 is adapted to 12/7. :)

(M+6)/36=(p-7)/21
<=> M+6 = 36*(p-7)/21
<=> M = 12/7*p - 18


There is something with my algebra.... i cannot get -18....


Write it here :)... Perhaps we could see something in :)
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 [#permalink] New post 19 Oct 2006, 13:56
m+6=36*(p-7)/21... simplify 21 and 36 to 7 and 12 respectively
m+6=12*(p-7)/7
m+6=(12p-84)/7
m=((12p-84)/7)-6..... from here you can see that there is no way to get -18... getting stupid? :)
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 [#permalink] New post 19 Oct 2006, 13:59
Fig wrote:
(E) if the typo 7/12 is adapted to 12/7. :)

(M+6)/36=(p-7)/21
<=> M+6 = 36*(p-7)/21
<=> M = 12/7*p - 18


Thanks Fig. That makes it work.

So from (M+6)/36=(p-7)/21 I picked numbers

M=66 AND P=49

Then M = 12/7*p - 18

66=(12/7)p-18
66=84-18
66=66 check this works :lol:
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 [#permalink] New post 19 Oct 2006, 14:00
SimaQ wrote:
m+6=36*(p-7)/21... simplify 21 and 36 to 7 and 12 respectively
m+6=12*(p-7)/7
m+6=(12p-84)/7
m=((12p-84)/7)-6..... from here you can see that there is no way to get -18... getting stupid? :)


From this line, u should perhaps distribute first the 1/7....
m+6=12*(p-7)/7
<=> m+6=12*(p-7)*1/7
<=> m+6=12*(p*1/7-7*1/7)
<=> m+6 = 12*p/7 - 12
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 [#permalink] New post 19 Oct 2006, 14:04
Fig wrote:
SimaQ wrote:
m+6=36*(p-7)/21... simplify 21 and 36 to 7 and 12 respectively
m+6=12*(p-7)/7
m+6=(12p-84)/7
m=((12p-84)/7)-6..... from here you can see that there is no way to get -18... getting stupid? :)


From this line, u should perhaps distribute first the 1/7....
m+6=12*(p-7)/7
<=> m+6=12*(p-7)*1/7
<=> m+6=12*(p*1/7-7*1/7)
<=> m+6 = 12*p/7 - 12


However it is interesting, that it does not work my way...
Actually i took the right approach, but could not get this answer and that is why i made a mistake....
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 [#permalink] New post 19 Oct 2006, 14:11
SimaQ wrote:
Fig wrote:
SimaQ wrote:
m+6=36*(p-7)/21... simplify 21 and 36 to 7 and 12 respectively
m+6=12*(p-7)/7
m+6=(12p-84)/7
m=((12p-84)/7)-6..... from here you can see that there is no way to get -18... getting stupid? :)


From this line, u should perhaps distribute first the 1/7....
m+6=12*(p-7)/7
<=> m+6=12*(p-7)*1/7
<=> m+6=12*(p*1/7-7*1/7)
<=> m+6 = 12*p/7 - 12


However it is interesting, that it does not work my way...
Actually i took the right approach, but could not get this answer and that is why i made a mistake....


Your way works... I would like to say that u make it a little harder ;) because, first u make 12*7 to get 84 and then to simplify, u need to express 84 = 7*12 :)

m=((12p-84)/7)-6
<=> m = ((12*p-7*12)*1/7)-6
<=> m = (12*1/7*p-12*7*1/7)-6
<=> m = 12/7*p - 12 -6
<=> m = 12/7*p - 18
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 [#permalink] New post 19 Oct 2006, 14:21
Matrix02 wrote:
Fig wrote:
(E) if the typo 7/12 is adapted to 12/7. :)

(M+6)/36=(p-7)/21
<=> M+6 = 36*(p-7)/21
<=> M = 12/7*p - 18


Thanks Fig. That makes it work.

So from (M+6)/36=(p-7)/21 I picked numbers

M=66 AND P=49

Then M = 12/7*p - 18

66=(12/7)p-18
66=84-18
66=66 check this works :lol:



Whoa - The algebra way is tough! Picking numbers worked best for me (although sometime it can be time consuming). Then you don't have to work off the 1st equation and just plug in values for p in the answer choices.
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 [#permalink] New post 19 Oct 2006, 14:42
Matrix02 wrote:
Matrix02 wrote:
Fig wrote:
(E) if the typo 7/12 is adapted to 12/7. :)

(M+6)/36=(p-7)/21
<=> M+6 = 36*(p-7)/21
<=> M = 12/7*p - 18


Thanks Fig. That makes it work.

So from (M+6)/36=(p-7)/21 I picked numbers

M=66 AND P=49

Then M = 12/7*p - 18

66=(12/7)p-18
66=84-18
66=66 check this works :lol:



Whoa - The algebra way is tough! Picking numbers worked best for me (although sometime it can be time consuming). Then you don't have to work off the 1st equation and just plug in values for p in the answer choices.


The most important is that u feel fine with one or your way and that is fast enough :)
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 [#permalink] New post 19 Oct 2006, 14:48
21(M+6)=36(p-7)
21M+21(6)=36p-36(7)
3M+3(6)=36p/7 - 36
3M=36p/7 - 54
M=12p/7 - 18
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 [#permalink] New post 19 Oct 2006, 20:20
definitely a typo, inform the author of the problem so that he can fix it :D
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 [#permalink] New post 27 May 2007, 20:30
londonluddite wrote:
21(M+6)=36(p-7)
21M+21(6)=36p-36(7)
3M+3(6)=36p/7 - 36
3M=36p/7 - 54
M=12p/7 - 18


wow. i hate these MAJOR typos in this PS1000 packet...thanks for clearing it up
  [#permalink] 27 May 2007, 20:30
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