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The expenses of a hostel are partly fixed and partly

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The expenses of a hostel are partly fixed and partly [#permalink] New post 14 Aug 2012, 11:20
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The expenses of a hostel are partly fixed and partly variable. It costs $120 per head per day if there are 20 students and $110 per head per day if there are 25 students. What will be the cost per head per day if the number of students increases to 40?

A. 105
B. 100
C. 95
D. 80
E. 75
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 14 Aug 2012, 12:48
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NYC5648 wrote:
The expenses of a hostel are partly fixed and partly variable. It costs $120 per head per day if there are 20 students and $110 per head per day if there are 25 students. What will be the cost per head per day if the number of students increases to 40?

A. 105
B. 100
C. 95
D. 80
E. 75


Say the fixed cost is $x and the variable cost is $y per head. Then:

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+20y}{20}=120 --> x+20y=20*120;

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+25y}{25}=110 --> x+25y=25*110;

Subtract the first equation from the second: 5y=25*110-20*120 --> y=70 --> x=1,000.

Therefore the cost per head per day for 40 students will be \frac{x+40y}{y}=\frac{1,000+40*70}{40}=95.

Answer: C.
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 18 Aug 2012, 00:40
Thank you Bunuel! Totally clear now!
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 18 Aug 2012, 07:02
Bunuel wrote:
NYC5648 wrote:
The expenses of a hostel are partly fixed and partly variable. It costs $120 per head per day if there are 20 students and $110 per head per day if there are 25 students. What will be the cost per head per day if the number of students increases to 40?

A. 105
B. 100
C. 95
D. 80
E. 75


Say the fixed cost is $x and the variable cost is $y per head. Then:

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+20y}{20}=120 --> x+20y=20*120;

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+25y}{25}=110 --> x+25y=25*110;

Subtract the first equation from the second: 5y=25*110-20*120 --> y=70 --> x=1,000.

Therefore the cost per head per day for 40 students will be \frac{x+40y}{y}=\frac{1,000+40*70}{40}=95.

Answer: C.


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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 18 Aug 2012, 08:53
+1 C

Fixed costs: $ 1,000
Variable costs per head: $70
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 25 Feb 2014, 09:59
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 28 Feb 2014, 02:17
Bunuel wrote:
NYC5648 wrote:
The expenses of a hostel are partly fixed and partly variable. It costs $120 per head per day if there are 20 students and $110 per head per day if there are 25 students. What will be the cost per head per day if the number of students increases to 40?

A. 105
B. 100
C. 95
D. 80
E. 75


Say the fixed cost is $x and the variable cost is $y per head. Then:

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+20y}{20}=120 --> x+20y=20*120;

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+25y}{25}=110 --> x+25y=25*110;

Subtract the first equation from the second: 5y=25*110-20*120 --> y=70 --> x=1,000.

Therefore the cost per head per day for 40 students will be \frac{x+40y}{y}=\frac{1,000+40*70}{40}=95.

Answer: C.



Can you kindly explain how 20y & 25y are taken?
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 28 Feb 2014, 02:26
Expert's post
PareshGmat wrote:
Bunuel wrote:
NYC5648 wrote:
The expenses of a hostel are partly fixed and partly variable. It costs $120 per head per day if there are 20 students and $110 per head per day if there are 25 students. What will be the cost per head per day if the number of students increases to 40?

A. 105
B. 100
C. 95
D. 80
E. 75


Say the fixed cost is $x and the variable cost is $y per head. Then:

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+20y}{20}=120 --> x+20y=20*120;

cost \ per \ head=\frac{total \ cost}{# \ of \ students}=\frac{x+25y}{25}=110 --> x+25y=25*110;

Subtract the first equation from the second: 5y=25*110-20*120 --> y=70 --> x=1,000.

Therefore the cost per head per day for 40 students will be \frac{x+40y}{y}=\frac{1,000+40*70}{40}=95.

Answer: C.



Can you kindly explain how 20y & 25y are taken?


The variable cost is $y per head, thus for 20 students it's 20y and for 25 students it's 25y.

Hope it's clear.
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Re: The expenses of a hostel are partly fixed and partly [#permalink] New post 28 Jun 2014, 05:49
I solved the problem using an approach similar to Bunuel's. However, it took me 2:31 min to read the question and solve the problem. I wonder if there is a faster way to solve this problem because these additional seconds (~31 seconds) all add up.

My steps:
F + 20 * V = 120 * 20
F + 25 * V = 110 * 25

5 * V = 50 (55 - 12 * 4)
5 * V = 50 * 7
V = 70
F = 2400 - 1400 = 1000
Total = 1000 + 70 * 40 = 3800
At this time I looked at the answer choice and did not see anything matching :) and quickly realized I need per head cost
So I divided the above result by 40 to get 95.

I could potentially save few seconds if I am more alert but I still feel the above steps would take me 2 min or more.

I would like to know how much time other people are taking to solve the same problem
Re: The expenses of a hostel are partly fixed and partly   [#permalink] 28 Jun 2014, 05:49
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