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Hi everyone, I wanted to make you a quick and apparently easy question that it's giving me a hard time:

What is the angle formed by the diagonals of to perpendicular faces of a cube?

I know the answer but I can't visualize why that's the answer

Source: local GMAT course

Thanks in advance

Added a question about this issue for a better understating.

Attachment:

Cube.jpg [ 30.11 KiB | Viewed 5623 times ]

The figure above is a cube. What is the measure of angle BEG (not shown)? A. 30° B. 45° C. 60° D. 75° E. 90°

Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.

Re: The figure above is a cube. What is the measure of angle BEG [#permalink]

Show Tags

26 Mar 2012, 07:35

Thank you Bunuel, for the edit and for the answer. As the image provided in the exercise was not clear I was misinterpreting the angle that the question was asking to identify, this makes total sense now.

Hi everyone, I wanted to make you a quick and apparently easy question that it's giving me a hard time:

What is the angle formed by the diagonals of to perpendicular faces of a cube?

I know the answer but I can't visualize why that's the answer

Source: local GMAT course

Thanks in advance

Added a question about this issue for a better understating.

Attachment:

Cube.jpg

The figure above is a cube. What is the measure of angle BEG (not shown)? A. 30° B. 45° C. 60° D. 75° E. 90°

Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.

Answer: C.

Hope it helps.

Why isn't it 90? Since two diagonals bisect two 90 degree angles would the x angle equal to 90? I understand your explanation, but would like to understand why my thinking is wrong? Thank you.

Hi everyone, I wanted to make you a quick and apparently easy question that it's giving me a hard time:

What is the angle formed by the diagonals of to perpendicular faces of a cube?

I know the answer but I can't visualize why that's the answer

Source: local GMAT course

Thanks in advance

Added a question about this issue for a better understating.

Attachment:

The attachment Cube.jpg is no longer available

The figure above is a cube. What is the measure of angle BEG (not shown)? A. 30° B. 45° C. 60° D. 75° E. 90°

Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.

Answer: C.

Hope it helps.

Why isn't it 90? Since two diagonals bisect two 90 degree angles would the x angle equal to 90? I understand your explanation, but would like to understand why my thinking is wrong? Thank you.

It would be correct for 2-D geometry, meaning the angle between two diagonals below is indeed 90 degrees:

Attachment:

Squares.png [ 2.5 KiB | Viewed 5276 times ]

But in 3-D geometry 2 faces are already 90 degrees to each other thus their diagonals would not form 90 degrees any more.

Re: The figure above is a cube. What is the measure of angle BEG [#permalink]

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07 Oct 2016, 19:28

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