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The figure above is composed of 6 squares, each with side s

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The figure above is composed of 6 squares, each with side s [#permalink] New post 29 Nov 2010, 16:05
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The figure above is composed of 6 squares, each with side s centimeters. If the number of centimeters in the perimeter of the figure is equal to the number of square centimeters in its area, what is the value of s?

A. 1
B. 5/3
C. 2
D. 5/2
E. 7/3
[Reveal] Spoiler: OA

Last edited by Bunuel on 09 Dec 2012, 05:58, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Perimeter vs Area [#permalink] New post 29 Nov 2010, 16:40
The figure above is composed of 6 squares, each with side s centimeters. If the number of centimeters in the perimeter of the figure is equal to the number of square centimeters in its area, what is the value of s?

A. 1
B. 5/3
C. 2
D. 5/2
E. 7/3

Area of the figure is 6s^2 square centimeters, as there are 6 little squares and each has the are of s^2 (alternately you can notice that the figure shown is just a rectangle 2s*3s, with one little square moved on top, so area remained the same as that of a rectangle);

As for the perimeter: it equals to the perimeter of rectangle (p=2(2s+3s)=10s) plus 4s, so to 14s (again alternately you can just count the number of exposed sides to get the perimeter);

So, we are told that area=perimeter --> 6s^2=14s --> s=7/3.

Answer: E.
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Re: Perimeter vs Area [#permalink] New post 29 Nov 2010, 22:14
yep, thats how I did it 14s=6s^2 so s=7/3
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Re: Perimeter vs Area [#permalink] New post 09 Dec 2012, 05:17
Bunuel I am getting 19s for the perimeter
What's wrong with me
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Re: Perimeter vs Area [#permalink] New post 09 Dec 2012, 06:04
Ousmane wrote:
Bunuel I am getting 19s for the perimeter
What's wrong with me
Brother Karamazov


Look at the image below:
Attachment:
perimeter.png
perimeter.png [ 6.39 KiB | Viewed 342 times ]
As you can see there are 14 sides exposed, thus the perimeter of the figure is 14s.

Hope it helps.
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Re: Perimeter vs Area   [#permalink] 09 Dec 2012, 06:04
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