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The figure above represents a square garden that is divided

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Senior Manager
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The figure above represents a square garden that is divided [#permalink]

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New post 15 Sep 2007, 16:20
00:00
A
B
C
D
E

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(N/A)

Question Stats:

67% (01:03) correct 33% (02:38) wrong based on 20 sessions

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The figure above represents a square garden that is divided into 9 rectangular regions with indicated dimensions in meters. The shaded regions are planted with peas, and the unshaded regions are planted with tomatoes. If the sum of the areas of the regions planted with peas is equal to the sum of the areas of the regions planted with tomatoes, what is the value of x?

A. 0.5
B. 1
C. 1.5
D. 2
E. 2.5
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New post 15 Sep 2007, 16:51
areas of shaded region
3*3+3*3+(6-x)3+3*x+3*x=36+3x

the area of unshaded region
3*3+(6-x)3+(6-x)3+3*x=45-3x

now S1=S2

36+3x=45-3x
6x=9
x=1.5

C

Last edited by Ravshonbek on 15 Sep 2007, 16:52, edited 1 time in total.
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New post 15 Sep 2007, 16:51
shaded regions = (9-3-x)*3+3*3+3*3+3x+3x = 18-3x+18+6x

unshaded regions = (9-3-x)*3+(9-3-x)*3+3*3+3x = 18-3x+18-3x+9+3x

since:

shaded regions = unshaded regions

18-3x+18+6x = 18-3x+18-3x+9+3x

36+3x = 36-6x+9+3x

9 = 6x

x = 1.5

the answer is (C)



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New post 16 Sep 2007, 08:55
nice works..now why didnt i think of solving it this way??
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New post 16 Sep 2007, 11:46
OA is indeed C.
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New post 16 Sep 2007, 18:30
Key is "square garden". :-)

- Brajesh
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New post 16 Sep 2007, 23:08
Ans :C.

Attachment is my working.
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New post 16 Sep 2007, 23:23
ywilfred wrote:
Ans :C.

Attachment is my working.


Nice work !

:)
  [#permalink] 16 Sep 2007, 23:23
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