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# The figure above represents a square garden that is divided

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The figure above represents a square garden that is divided [#permalink]

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15 Sep 2007, 16:20
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Difficulty:

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Question Stats:

67% (01:03) correct 33% (02:38) wrong based on 20 sessions

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The figure above represents a square garden that is divided into 9 rectangular regions with indicated dimensions in meters. The shaded regions are planted with peas, and the unshaded regions are planted with tomatoes. If the sum of the areas of the regions planted with peas is equal to the sum of the areas of the regions planted with tomatoes, what is the value of x?

A. 0.5
B. 1
C. 1.5
D. 2
E. 2.5
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Q8.jpg [ 6.48 KiB | Viewed 7363 times ]

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15 Sep 2007, 16:51
3*3+3*3+(6-x)3+3*x+3*x=36+3x

3*3+(6-x)3+(6-x)3+3*x=45-3x

now S1=S2

36+3x=45-3x
6x=9
x=1.5

C

Last edited by Ravshonbek on 15 Sep 2007, 16:52, edited 1 time in total.
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15 Sep 2007, 16:51
shaded regions = (9-3-x)*3+3*3+3*3+3x+3x = 18-3x+18+6x

unshaded regions = (9-3-x)*3+(9-3-x)*3+3*3+3x = 18-3x+18-3x+9+3x

since:

18-3x+18+6x = 18-3x+18-3x+9+3x

36+3x = 36-6x+9+3x

9 = 6x

x = 1.5

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16 Sep 2007, 08:55
nice works..now why didnt i think of solving it this way??
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16 Sep 2007, 11:46
OA is indeed C.
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16 Sep 2007, 18:30
Key is "square garden".

- Brajesh
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16 Sep 2007, 23:08
Ans :C.

Attachment is my working.
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plot.doc [37.5 KiB]

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16 Sep 2007, 23:23
ywilfred wrote:
Ans :C.

Attachment is my working.

Nice work !

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