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The figure above shows a construction plan for the intersect [#permalink]

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17 Jan 2013, 06:33

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C

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76% (01:40) correct
24% (01:06) wrong based on 177 sessions

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Roads.png [ 25.68 KiB | Viewed 5890 times ]

The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

Re: The figure above shows a construction plan for the intersect [#permalink]

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17 Jan 2013, 07:33

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The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient. (2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:

Attachment:

Roads.png [ 14.39 KiB | Viewed 4081 times ]

From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Re: The figure above shows a construction plan for the intersect [#permalink]

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18 Jan 2013, 04:37

Seems a very basic question, but what other possible concepts are tested here? The official explanations was pretty convoluted had a parallelogram and all of that. _________________

Re: The figure above shows a construction plan for the intersect [#permalink]

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18 Jan 2013, 23:05

Bunuel wrote:

The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient. (2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:

Attachment:

Roads.png

From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.

Bunnel

I have small doubt here

Suppose the length is not 0 then you will have two variables and you cannot solve the equation i.e the equation becomes

Suppose width=X

Then T= 360-3X-R-S

and here you have 2 variables and 1 equation you cannot get a single solution

Re: The figure above shows a construction plan for the intersect [#permalink]

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19 Jan 2013, 04:58

Expert's post

mydreammba wrote:

Bunuel wrote:

The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient. (2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:

Attachment:

Roads.png

From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.

Bunnel

I have small doubt here

Suppose the length is not 0 then you will have two variables and you cannot solve the equation i.e the equation becomes

Suppose width=X

Then T= 360-3X-R-S

and here you have 2 variables and 1 equation you cannot get a single solution

Am i right?

No you are not. The edges of the road are parallel, so there is 0 degree angle between them. _________________

Re: The figure above shows a construction plan for the intersect [#permalink]

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19 Jan 2013, 07:57

Bunuel wrote:

mydreammba wrote:

Bunuel wrote:

The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140. Not sufficient. (2) s = 160. Not sufficient.

(1)+(2) Consider the width of the roads to be 0 as shown below:

Attachment:

Roads.png

From the figure we have that r+s+t=360 degrees --> 140+160+t=360 --> t=60 degrees. Sufficient.

Answer: C.

Bunnel

I have small doubt here

Suppose the length is not 0 then you will have two variables and you cannot solve the equation i.e the equation becomes

Suppose width=X

Then T= 360-3X-R-S

and here you have 2 variables and 1 equation you cannot get a single solution

Am i right?

No you are not. The edges of the road are parallel, so there is 0 degree angle between them.

Re: The figure above shows a construction plan for the intersect [#permalink]

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25 Sep 2014, 22:55

Expert's post

piyusharma wrote:

Hi Guys,

I assumed Angle R = Angle S due to the parallel lines property. Hence for me each statement was sufficient. Why is R not equal to S?

Also note that in DS questions, the two statements never contradict each other. If you had assumed that angle R = angle S, the two statements should have told you that that is not true. Statement 1 tells you that angle R is 140. According to you, then angle S should be 140 too. But statement 2 tells you that angle S is 160. This means there is something wrong in your assumption. _________________

Re: The figure above shows a construction plan for the intersect [#permalink]

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21 Oct 2015, 04:34

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: The figure above shows a construction plan for the intersect [#permalink]

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25 Oct 2015, 11:56

Expert's post

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Attachment:

Roads.png [ 25.68 KiB | Viewed 693 times ]

The figure above shows a construction plan for the intersection of three straight roads, each having parallel edges and each having the same width. what is the value of t?

(1) r = 140 (2) s = 160

From the original condition, we can see that there are 3 variables (r,s,t), and one equation (r+s+t=360), so we need 2 more equations, which are given from the 2 conditions, so there is high chance (C) will be our answer. Looking at the conditions together, r+s+t=140+160+t=360, so it answers the question 'yes', and the answer becomes (C).

For cases where we need 2 more equation, such as original conditions with “2 variables”, or “3 variables and 1 equation”, or “4 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 70% chance that C is the answer, while E has 25% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since C is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, D or E. _________________

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