tarek99 wrote:

The figure above shows a rectangular garden that is comprised of a central plot and a border surrounding the central plot; the border and the central plot have the same area. The garden has length 25 feet and width 20 feet. If the length and width of the central plot have the same ratio as the length and width of the garden, what is the length of the central plot, in feet?

a) 25 sqrt(2)

b) 20 sqrt(2)

c) 20(1-sqrt(2))

d) ( 25 sqrt(2) ) / 2

e) (25/2) ( 25/2)

Please show your steps

z is the width of the frame. X is the length of the picture, Y is the width of the picture.

x+2z=25 y+2z=20 x/y=25/20 --> 5w/4w w is a multiplier.

25*20= total area so 500 -(x*y) = x*y so x*y=250.

x-y=5 y=x-5 --> x(x-5)=250 --> x^2-5x-250=0

From here I dont really know how to solve this quadratic.

I did what Raffie did. Only D works