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# The figure above shows the dimensions of a rectangular board

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The figure above shows the dimensions of a rectangular board [#permalink]

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24 Aug 2005, 15:41
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The figure above shows the dimensions of a rectangular board that is to be cut into four identical pieces by making cuts at points A, B, and C, as indicated. If x = 45, what is the length AB ?
(1 foot = 12 inches)
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Rectangle.doc [30 KiB]

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24 Aug 2005, 16:21
180 inches or 15 feet
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24 Aug 2005, 17:15
(A) 5 ft 6 in
(B) 5 ft in
(C) 5 ft 3 in
(D) 5 ft
(E) 4 ft 9 in

riteshgupta1
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24 Aug 2005, 17:51
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1) The area of each of the 4 identical pieces is (20(12) x 6) / 4 = 360 sq inches.

2) Daw a vertical line between line segment AB to form an isosceles triangle and a rectangle. Divide AB into say, AD and DB.

3) Area of the triangle is (6 x 6) /2 = 18 sq inches and segment AD = 6 inches.

4) Area of the rectangle = 360 - 18 = 342 sq inches. Therefore DB = 342 / 6 = 57 inches.

5) AB = AD + DB = 6 + 57 = 63 inches or 5 ft 3 in
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25 Aug 2005, 05:04
one more C

(x+x-6)*6/2=(20*6*12)/4
25 Aug 2005, 05:04
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