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The figure shown represents a board with 4 rows of pegs, and

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The figure shown represents a board with 4 rows of pegs, and [#permalink] New post 13 Oct 2006, 10:33
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46% (02:12) correct 53% (00:43) wrong based on 2 sessions
The figure shown represents a board with 4 rows of pegs, and at the bottom of the board are 4 cells numbered 1 to 4. Whenever the ball shown passes through the opening between two adjacent pegs in the same row, it will hit the peg directly beneath the opening. The ball then has the probability 1/2 of passing through the opening immediately to the left of that peg and probability 1/2 of passing through the opening immediately to the right. What is the probability that when the ball passes through the first two pegs at the top it will end in Cell 2?

A. 1/16
B. 1/8
C. 1/4
D. 3/8
E. 1/2[attachment=0]Pegs.PNG[/attachment]
[Reveal] Spoiler: OA

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Pegs.PNG
Pegs.PNG [ 9.87 KiB | Viewed 1496 times ]


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Last edited by Bunuel on 19 Feb 2012, 13:10, edited 1 time in total.
Edited the question and added the OA
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 [#permalink] New post 13 Oct 2006, 10:42
think its 3/8.

8 ways the ball lands in any of the cells.
only 3 ways does the ball land in cell two
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 [#permalink] New post 13 Oct 2006, 11:22
not sure i woul have got this without making a mistake, but......

1st gate, left or right

if it goes left it can then go : LR or RL

if it goes right it can then go : LL

so

LLR
LRL
RLL

(1/2 * 1/2 * 1/2) * 3

= 3/8
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 [#permalink] New post 13 Oct 2006, 11:28
The same logice...... must be 3/8

There is only 1 chance each to fall in 1 and 4
There are 3 chances to fall in 2 and 3.

So totally 8 out of which we need 3

So 3/8
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 [#permalink] New post 14 Oct 2006, 03:36
you're right

the OA is 3/8

I had a dificulty to count the 8 ways during the test.
I tried to put in a formula, though I'm not sure it makes some sense
4!/2*3 =8
any shortcut?
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Re: probability toughy one from OG [#permalink] New post 19 Feb 2012, 13:01
Does anyone know which OG question this is ?
I haven't come across this in either 10th or 12th edition or Quant Review 2nd edition !
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Re: The figure shown represents a board with 4 rows of pegs, and [#permalink] New post 19 Feb 2012, 13:13
ugo_castelo wrote:
The figure shown represents a board with 4 rows of pegs, and at the bottom of the board are 4 cells numbered 1 to 4. Whenever the ball shown passes through the opening between two adjacent pegs in the same row, it will hit the peg directly beneath the opening. The ball then has the probability 1/2 of passing through the opening immediately to the left of that peg and probability 1/2 of passing through the opening immediately to the right. What is the probability that when the ball passes through the first two pegs at the top it will end in Cell 2?

A. 1/16
B. 1/8
C. 1/4
D. 3/8
E. 1/2
Attachment:
Pegs.PNG


When ball passes two pegs it will be either on the left route or on the right route. Now, if ball is on the left route, number of possible scenarios will be 4, out of which two will lead to cell 2, if ball is on the right route, number of scenarios will also be 4, but out of these four only one will lead to cell 2. So, total 8 scenarios out of which 2+1=3 lead to cell 2, hence probability 3/8.

Answer: D.

morya003 wrote:
Does anyone know which OG question this is ?
I haven't come across this in either 10th or 12th edition or Quant Review 2nd edition !


I think it's from GMAT Prep, not OG.
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Re: The figure shown represents a board with 4 rows of pegs, and [#permalink] New post 19 Feb 2012, 16:35
If a question is accompanied by a helpful picture, you can sometimes arrive at the answer simply by visualizing what's said to be happening in the picture. Concentrate and picture the ball dropping through those openings, landing on the peg and then taking a right or a left direction. Note the direction as it is dropping- LLR, for example. You will notice that the ball can turn left and left and right OR left and right and left OR right and left and left in order to land on Cell 2. For "AND" you know you have to multiply and for "OR" you know you have to add. So (1/2*1/2*1/2) + (1/2*1/2*1/2)+ (1/2*1/2*1/2). That's 3/8!
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The figure shown represents a board with 4 rows of pegs, and [#permalink] New post 10 May 2012, 04:33
Probability of going left of peg = 1/2
probability of going right of peg = 1/2

After passing the first row, ball will hit a peg. so the probability of going left or right is 1/2.
Assume that ball goes to left:

Then the favorable outcome can be ball first going left then going right or ball first going right and then going left. Hence probability of ball hitting cell 2 after taking first left is = 1/2*1/2 = 1/4.

Now assume that ball goes to right:

The favorable outcome after taking right will be to take 2 left on next two pegs.
hence probability of hitting cell 2 after taking first right is 1/4 *1/2 =1/8

So the total probability = 1/8+1/4 =3/8
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The figure shown represents a board with 4 rows of pegs, and   [#permalink] 10 May 2012, 04:33
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