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# The front of a 6-foot-by-8-foot rectangular door has brass

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The front of a 6-foot-by-8-foot rectangular door has brass [#permalink]

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12 Dec 2012, 08:45
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45% (medium)

Question Stats:

64% (02:43) correct 36% (01:29) wrong based on 633 sessions

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Door.png [ 6.35 KiB | Viewed 9416 times ]
The front of a 6-foot-by-8-foot rectangular door has brass rectangular trim, as indicated by the shading in the figure above. If the trim is uniformly 1 foot wide, what fraction of the door's front surface is covered by the trim?

(A) 13/48
(B) 5/12
(C) 1/2
(D) 7/12
(E) 5/8
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Re: The front of a 6-foot-by-8-foot rectangular door has brass [#permalink]

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29 Oct 2014, 02:03
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Segmented the shaded region in 2 as shown below:
Attachment:

Door.png [ 5.29 KiB | Viewed 4838 times ]

Yellow region area = 2 * 8*1 = 16

Pink region area = 3 * 4*1 = 12

Total frame area = 8*6 = 48

Ratio $$= \frac{28}{48} = \frac{7}{12}$$

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Re: The front of a 6-foot-by-8-foot rectangular door has brass [#permalink]

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12 Dec 2012, 08:52
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The front of a 6-foot-by-8-foot rectangular door has brass rectangular trim, as indicated by the shading in the figure above. If the trim is uniformly 1 foot wide, what fraction of the door's front surface is covered by the trim?

(A) 13/48
(B) 5/12
(C) 1/2
(D) 7/12
(E) 5/8

First let's find the area of unshaded region.

The two unshaded regions have a width of 4 feet: 6 feet minus 1 foot wide trim on each side.
The two unshaded regions have a height of 5 feet: 8 feet minus 1 foot at the top, 1 foot in the middle and 1 foot at the bottom.

Thus the area of the two unshaded regions is 4*5=20 square feet.

Therefore, the area of the trim is 6*8-20=28 square feet, which is 28/48=7/12 of the total area.

Hope it's clear.
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Re: The front of a 6-foot-by-8-foot rectangular door has brass [#permalink]

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28 Oct 2014, 17:13
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Bunuel wrote:

The front of a 6-foot-by-8-foot rectangular door has brass rectangular trim, as indicated by the shading in the figure above. If the trim is uniformly 1 foot wide, what fraction of the door's front surface is covered by the trim?

(A) 13/48
(B) 5/12
(C) 1/2
(D) 7/12
(E) 5/8

First let's find the area of unshaded region.

The two unshaded regions have a width of 4 feet: 6 feet minus 1 foot wide trim on each side.
The two unshaded regions have a height of 5 feet: 8 feet minus 1 foot at the top, 1 foot in the middle and 1 foot at the bottom.

Thus the area of the two unshaded regions is 4*5=20 square feet.

Therefore, the area of the trim is 6*8-20=28 square feet, which is 28/48=7/12 of the total area.

Hope it's clear.

Thank you for this. I accidently chose the trap answer of $$\frac{5}{12}$$, and found the area of the door not covered by trim
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Re: The front of a 6-foot-by-8-foot rectangular door has brass [#permalink]

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06 May 2014, 12:34
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Re: The front of a 6-foot-by-8-foot rectangular door has brass [#permalink]

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18 Dec 2015, 08:11
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The front of a 6-foot-by-8-foot rectangular door has brass   [#permalink] 18 Dec 2015, 08:11
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