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The graphs of y = -3 + |x-3| and y = 1/2 * |x-3| enclose an

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Manager
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The graphs of y = -3 + |x-3| and y = 1/2 * |x-3| enclose an [#permalink] New post 26 Apr 2006, 08:49
The graphs of

y = -3 + |x-3| and
y = 1/2 * |x-3|

enclose an area in the xy-plane that's divided by the x-axis.
What's the ratio of the part above the x-axis to the part below it?

A) 2 : 1

B) sqrt(2) : 1

C) 1 : 1

D) 1 : sqrt(3)

E) 1 : 2
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 [#permalink] New post 26 Apr 2006, 09:51
C. The ratio of areas is 1:1
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 [#permalink] New post 26 Apr 2006, 09:58
same here C i also got 1:1

the area ratio was 9/9 so 1:1
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 [#permalink] New post 26 Apr 2006, 11:19
You are both right.

Just to add the picture:
Attachments

tri.jpg
tri.jpg [ 15 KiB | Viewed 356 times ]

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 [#permalink] New post 26 Apr 2006, 11:39
Seems like a lot of work. Do such Questions appear in GMAT?
  [#permalink] 26 Apr 2006, 11:39
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The graphs of y = -3 + |x-3| and y = 1/2 * |x-3| enclose an

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