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The inside of a rectangular carton is 48 centimeters long [#permalink]
18 Aug 2009, 02:08
1
This post was BOOKMARKED
00:00
A
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D
E
Difficulty:
15% (low)
Question Stats:
82% (01:50) correct
18% (00:54) wrong based on 118 sessions
Attachment:
2009-08-18_170600.png [ 2.72 KiB | Viewed 5617 times ]
The inside of a rectangular carton is 48 centimeters long, 32 centimeters wide, and 15 centimeters high. The carton is filled to capacity with k identical cylindrical cans of fruit that stand upright in rows and columns, as indicated in the figure above. If the cans are 15 centimeters high, what is the value of k ?
(1) Each of the cans has a radius of 4 centimeters. (2) Six of the cans fit exactly along the length of the carton.
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
18 Aug 2009, 02:12
Expert's post
Congratulations! I believe you are the first official tagger! Welcome to GMAT Club and thanks for pitching in and sorry for off-topic message _________________
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
18 Aug 2009, 04:49
I think the answer to the question is D.
Since (1) Each of the cans has a radius of 4 centimeters gives us the radius of each circle, then that means we can figure out the volume of each can. Thus able to find the value of k
(2) Six of the cans fit exactly along the length of the carton From this information we are able to find the radius of the can, as 6 cans which fit into the length (48) Thus also able to find the value of k, volume So the answer for official guide is correct. _________________
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
18 Aug 2009, 05:51
mirzohidjon wrote:
I think the answer to the question is D.
Since (1) Each of the cans has a radius of 4 centimeters gives us the radius of each circle, then that means we can figure out the volume of each can. Thus able to find the value of k ...
wrong.
The box is 48 centimeters long, 32 centimeters wide, and 15 centimeters high. Therefore, when the cans are put in, there would be three sides to stand on: the side consists with 48x32 or 32x15 or 48x15.
when the cans are put on side 48x32, K=(48/8)*(32/8)=24 when the cans are put on side 32x15, K=(32/8)*mod(15/8)=4 when the cans are put on side 48x15, K=(48/8)*mod(15/8)=6 the height of cans doesn't mean anything here.
actually the correct answer should be E. _________________
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
18 Aug 2009, 07:39
1
This post received KUDOS
Flying bunny, first of all, you CANNOT dispute GMAC/OFFICIAL GUIDE. I know thats a heard to digest lesson, but must be learnt if you want to succeed in GMAT.
So accept that the answer is D (if thats what OG says) and then proceed backwards to see where/what you did wrong.
Now coming to your explanation, here is why OA cannot be E. If the question did not state this - "The carton is filled to capacity with k identical cylindrical cans of fruit that stand upright in rows and columns", then your explanation will make sense.
But since the question clearly said that cans stand upright....that means they stand on their base. And hence the 15 cms height information is extremely important. Also, since the question also mentioned that the carton is filled to capacity, that means there are no gaps/voids.....it is tightly packed....and both STMT 1 and STMT 2 perfectly fit these measurements.
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
18 Aug 2009, 07:46
You gonna be kidding.
"The carton is filled to capacity with k identical cylindrical cans of fruit that stand upright in rows and columns", the cans stand upright, but the box can flip around. _________________
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
24 Mar 2012, 07:45
What is the exact part of the question that should lead the reader to understand that the base of the carton is a 48 cm x 32 cm rectangular? The figure has been suggested in this thread as the key part, but I believe that it is not possible to conclude the orientation of the carton from the figure.
Filled to capacity?
This question has been discussed also in another post but there is nothing helpful to answer my question. _________________
Re: Question 34 from "Official Guide for GMAT Review, 12th ed" [#permalink]
24 Mar 2012, 14:06
Expert's post
fcomorales wrote:
What is the exact part of the question that should lead the reader to understand that the base of the carton is a 48 cm x 32 cm rectangular? The figure has been suggested in this thread as the key part, but I believe that it is not possible to conclude the orientation of the carton from the figure.
Filled to capacity?
This question has been discussed also in another post but there is nothing helpful to answer my question.
Not sure that I understand your question correctly. The stem directly states that: "the inside of a RECTANGULAR carton is 48 centimeters long, 32 centimeters wide..." _________________
Re: The inside of a rectangular carton is 48 centimeters long [#permalink]
24 Mar 2012, 14:23
Hi Bunuel. Thanks for your reply.
In order to solve the problem is necessary to understand that the can's bottom is placed over a specific side of the carton (in this case, the one with dimensions 48 x 32 cm). What I don't know is why we have to know that the dimensions of the rectangular carton's bottom are 48 x 32 cm and not, for instance, 48 x 15 cm. Is it because of the words "long", "wide" and "high"?
If GMAT tells us that the carton is 15 cm high, then can we be sure that the base of the carton is the rectangular 48 x 32 cm?
Maybe I am overthinking the problem, but I want to know if the GMAT can trick you in this way. Another user raised this issue some of time ago in this thread.
Re: The inside of a rectangular carton is 48 centimeters long [#permalink]
25 Mar 2012, 02:58
1
This post received KUDOS
Expert's post
fcomorales wrote:
Hi Bunuel. Thanks for your reply.
In order to solve the problem is necessary to understand that the can's bottom is placed over a specific side of the carton (in this case, the one with dimensions 48 x 32 cm). What I don't know is why we have to know that the dimensions of the rectangular carton's bottom are 48 x 32 cm and not, for instance, 48 x 15 cm. Is it because of the words "long", "wide" and "high"?
Yes, this is exactly the reason. By the way this is an OG question and OG solution considers 48*32 to be the base. _________________
Re: The inside of a rectangular carton is 48 centimeters long [#permalink]
18 Dec 2013, 15:44
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Re: The inside of a rectangular carton is 48 centimeters long [#permalink]
19 Dec 2013, 00:25
Expert's post
2
This post was BOOKMARKED
The inside of a rectangular carton is 48 centimeters long, 32 centimeters wide, and 15 centimeters high. The carton is filled to capacity with k identical cylindrical cans of fruit that stand upright in rows and columns, as indicated in the figure above. If the cans are 15 centimeters high, what is the value of k?
(1) Each of the cans has a radius of 4 centimeters --> radius=4 means that diameter=8, which implies that along the 48 centimeter length of the carton 48/8=6 cans can be placed and along the 32 centimeter width of the carton 32/8=4 cans can be placed. Thus, k=6*4=24. Sufficient.
(2) Six of the cans fit exactly along the length of the carton --> the diameter of the can is 48/6=8 centimeters. So, we have the same info as above. Sufficient.
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