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The integers from 1 to 100 inclusive are each written on a [#permalink]
16 Oct 2006, 21:27

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The integers from 1 to 100 inclusive are each written on a single slip of paper and dropped into a jar. If one slip of paper is removed at random, approximately what is the probability that the number on it is neither even nor a multiple of 3
a) 83%
b) 67%
c) 50%
d)33%
e)17%

Total multiples of 2 = 50
Total multiples of 3 = 33
Now the numbers which are divisible by both 2 and 3 i.e numbers which are divisible by 6 are counted in the first 50 numbers as well as in the next 33 numbers. So we have to exclude the numbers that are divisible by 6 once from 50+33 =83

So total multiples of 6 =16

So 83-16 =67.

So there are 67 numbers which are either even or multiples of 3.

Why this is not true [#permalink]
17 Oct 2006, 13:46

If we negate this, we get "Even and multiple of 3", we have 16 numbers
(6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96). So this comes to 16/100. So for the answer (1-16/100=84/100). So why not 83% approx is the answer.I am just confused.Can any one correct me?