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# The integers m and p are such that 2 < m <p. m is not

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Senior Manager
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The integers m and p are such that 2 < m <p. m is not [#permalink]  08 Jun 2007, 09:00
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The integers m and p are such that 2 < m <p.
m is not a factor of p. r is the remainder when p is divided by m.
Q: Is r more than 1?

1) The greatest common factor of m and p is 2.
2) The least common multiple of m and p is 30.
Director
Joined: 26 Feb 2006
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Re: DS - remainder GMATPrep [#permalink]  08 Jun 2007, 22:29
Caas wrote:
The integers m and p are such that 2 < m <p.
m is not a factor of p. r is the remainder when p is divided by m.

Q: Is r more than 1?

1) The greatest common factor of m and p is 2.
2) The least common multiple of m and p is 30.

1. if the gratest common factor of m and p is 2, then m and p, both, are even. m and p can not be 4 and 8 cuz in that case the common factor is 4 not 2. therefore in that case r is obviously grater than 1. suff.

2. if the least common multiple of m and p is 30, m and p could be 5 and 6 respectively ot they could be 3 or 10 respectively or 15 and 30. so not suff.

So A.
Manager
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D.

Both are sufficient.

S1. m and n are 4,6 or 6,8 or 8,10 or 10,12 or 12,14
r>1
SUFF

S2. Only 2 combinations here.
5*6
3*10
Both r=1
SUFF
Director
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not necessarily is D correct. if m = 6 and p = 10.
Manager
Joined: 14 Mar 2007
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Youre right Himalayan
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