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# The interior of a rectangular carton is designed by a certai

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The interior of a rectangular carton is designed by a certai [#permalink]

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25 Feb 2011, 07:24
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The interior of a rectangular carton is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height of 3:2:2. In terms of x, which of the following equals the height of the carton, in feet?

A. 3√x
B. 3√[(2x)/3]
C. 3√[(3x)/2]
D. (2/3) 3√x
E. (3/2) 3√x
[Reveal] Spoiler: OA
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25 Feb 2011, 07:49
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Picking numbers:

If l = 3, w = 2 and h = 2, volume = 12.

Now, testing:

sq rt 12 = 2* sq rt 3 = approx 2*1.73 = approx 3.46
A) 3* sq rt 12 = approx 10.4 WRONG
B) 3 *sq rt 8 = approx 3 * 2.8 = 8.4 WRONG
C) 3 * sq rt 18 = approx 3 * 3*sq rt 2 = 3 * 4.2 = 12.6 WRONG
D) (2/3) * 3.46 = approx 2.3
E) (3/2) * 3.46 = approx 5.1

I would choose D, but it is not exact. Did I do anything wrong?
E)
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25 Feb 2011, 08:04
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naaga wrote:
The interior of a rectangular carton is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height of 3:2:2. In terms of x, which of the following equals the height of the carton, in feet?

A. 3√x
B. 3√[(2x)/3]
C. 3√[(3x)/2]
D. (2/3) 3√x
E. (3/2) 3√x

Given: $$length:width:height=3k:2k:2k$$, for some positive number $$k$$. Also: $$volume=x=3k*2k*2k$$ --> $$x=12k^3$$ --> $$k=\sqrt[3]{\frac{x}{12}}$$ --> $$height=2k=\sqrt[3]{\frac{2x}{3}}$$.

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25 Feb 2011, 09:36
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Ouch... I didn't understand the symbols.
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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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22 Dec 2013, 10:23
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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26 Sep 2015, 09:15
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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13 Mar 2016, 04:46
Hi Bunuel,

Could you suggest any way to master these questions? I seem to know how to deal with them, but make silly mistakes every single time.

Thanks!
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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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13 Mar 2016, 05:00
Expert's post
Viktoriaa wrote:
Hi Bunuel,

Could you suggest any way to master these questions? I seem to know how to deal with them, but make silly mistakes every single time.

Thanks!

Hi,
It will be important to know at what stage do you go wrong..
1)formula stage..
2)calculations..
3)difficulty with variables..

For example in this Qs..
things one should know.

1)formula for Volume of RECTANGULAR BOX..
2) converting ratio 3:2:2 to numeric values by multiplying each term by common variable..
3) What one has to be careful is to realize
a) it is not square root but 3rd root
b) height is 2 * variable ..

the other way to do is to take same value for common term in ratio. find the volume..
work backwards by substituting V in choices to get height.

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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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13 Mar 2016, 07:59
Hi,
It will be important to know at what stage do you go wrong..
1)formula stage..
2)calculations..
3)difficulty with variables..

For example in this Qs..
things one should know.

1)formula for Volume of RECTANGULAR BOX..
2) converting ratio 3:2:2 to numeric values by multiplying each term by common variable..
3) What one has to be careful is to realize
a) it is not square root but 3rd root
b) height is 2 * variable ..

the other way to do is to take same value for common term in ratio. find the volume..
work backwards by substituting V in choices to get height.
[/quote]

Hi,

Thanks a lot for such a detailed reply! I think I just go wrong with recognizing equations themselves - I mean, in this case, I new formula of the volume and paid attention to some tricky parts, but didn't use variable in 3:2:2... Probably just need more attention....
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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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16 Mar 2016, 15:57
Bunuel wrote:
naaga wrote:
The interior of a rectangular carton is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height of 3:2:2. In terms of x, which of the following equals the height of the carton, in feet?

A. 3√x
B. 3√[(2x)/3]
C. 3√[(3x)/2]
D. (2/3) 3√x
E. (3/2) 3√x

Given: $$length:width:height=3k:2k:2k$$, for some positive number $$k$$. Also: $$volume=x=3k*2k*2k$$ --> $$x=12k^3$$ --> $$k=\sqrt[3]{\frac{x}{12}}$$ --> $$height=2k=\sqrt[3]{\frac{2x}{3}}$$.

confused how you got from : $$k=\sqrt[3]{\frac{x}{12}}$$ --> $$height=2k=\sqrt[3]{\frac{2x}{3}}$$. can you break this down further please?
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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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16 Mar 2016, 19:45
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sagnik242 wrote:
Bunuel wrote:
naaga wrote:
The interior of a rectangular carton is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height of 3:2:2. In terms of x, which of the following equals the height of the carton, in feet?

A. 3√x
B. 3√[(2x)/3]
C. 3√[(3x)/2]
D. (2/3) 3√x
E. (3/2) 3√x

Given: $$length:width:height=3k:2k:2k$$, for some positive number $$k$$. Also: $$volume=x=3k*2k*2k$$ --> $$x=12k^3$$ --> $$k=\sqrt[3]{\frac{x}{12}}$$ --> $$height=2k=\sqrt[3]{\frac{2x}{3}}$$.

confused how you got from : $$k=\sqrt[3]{\frac{x}{12}}$$ --> $$height=2k=\sqrt[3]{\frac{2x}{3}}$$. can you break this down further please?

Hi,
$$k=\sqrt[3]{\frac{x}{12}}$$ ..
height is 2k as ratios are 3k:2k:2k
so $$2k=2\sqrt[3]{\frac{x}{12}}$$..
=> $$2k=\sqrt[3]{8}\sqrt[3]{\frac{x}{12}}$$..
$$2k=\sqrt[3]{\frac{8x}{12}}$$..
$$height=2k=\sqrt[3]{\frac{2x}{3}}$$..
hope this is what you were looking for
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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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04 May 2016, 21:45
Simple plug and play here

Choose the numbers given (3:2:2) = 12 for volume. Then, plug 12 into X in the answer choices to get 2.

cuberoot(2x/3) > cuberoot(2(12)/3) > cuberoot(24/3) > cuberoot (8) > 2

I immediately started with B, since it makes since (to find V, it'll be a cuberoot of something, with some division involved), and blamo it worked.
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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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05 May 2016, 04:59
naaga wrote:
The interior of a rectangular carton is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height of 3:2:2. In terms of x, which of the following equals the height of the carton, in feet?

A. 3√x
B. 3√[(2x)/3]
C. 3√[(3x)/2]
D. (2/3) 3√x
E. (3/2) 3√x

We are given that the ratio of length: width: height = 3 : 2 : 2 and we are also given that the volume of the rectangular solid is x. We can use n as the variable multiplier for our ratio, giving us:

length: width: height = 3n : 2n : 2n

Now we are ready to determine the height in terms of x.

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Re: The interior of a rectangular carton is designed by a certai [#permalink]

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05 May 2016, 10:37
volume = lbh
2k.3k.2k = x

k = cuberoot of x/12

2 times cuberoot of x/12 = 3√[(2x)/3]
Re: The interior of a rectangular carton is designed by a certai   [#permalink] 05 May 2016, 10:37
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