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# the large container game

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Senior Manager
Joined: 30 May 2005
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15 Jun 2005, 02:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

hello
a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5
(B) 4
(C) 3
(D) 2
( E)0

thanks
Director
Joined: 18 Apr 2005
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Location: Canuckland
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Re: the large container game [#permalink]

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15 Jun 2005, 02:38
mandy wrote:
:) hello
a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5
(B) 4
(C) 3
(D) 2
( E)0

thanks

they are all primes, 147000 is divisible by 7 twice
Senior Manager
Joined: 17 Apr 2005
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Re: the large container game [#permalink]

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15 Jun 2005, 07:12
147000 = 7^2 * 3 * 2^3 * 5^3.
Hence the no. of red beads in 2.

HMTG.
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Re: the large container game [#permalink]

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28 Jun 2005, 09:16
HowManyToGo wrote:
147000 = 7^2 * 3 * 2^3 * 5^3.
Hence the no. of red beads in 2.

HMTG.

hello
Please HowManyToGo can you explain me how you gets the powerfor this equation thanks :
Senior Manager
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28 Jun 2005, 09:19
Mandy,

147000 =147*1000 = 49 * 3 * 10^3= 7^2*3^1*5^3*2^3
Senior Manager
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28 Jun 2005, 09:40
AJB77 wrote:
Mandy,

147000 =147*1000 = 49 * 3 * 10^3= 7^2*3^1*5^3*2^3

thanks AJB it is prime factorisation
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