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the large container game [#permalink] New post 15 Jun 2005, 02:23
:) hello
:? a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5
(B) 4
(C) 3
(D) 2
( E)0


thanks
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Re: the large container game [#permalink] New post 15 Jun 2005, 02:38
mandy wrote:
:) hello
:? a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5
(B) 4
(C) 3
(D) 2
( E)0


thanks


they are all primes, 147000 is divisible by 7 twice
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Re: the large container game [#permalink] New post 15 Jun 2005, 07:12
147000 = 7^2 * 3 * 2^3 * 5^3.
Hence the no. of red beads in 2.

HMTG.
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Re: the large container game [#permalink] New post 28 Jun 2005, 09:16
HowManyToGo wrote:
147000 = 7^2 * 3 * 2^3 * 5^3.
Hence the no. of red beads in 2.

HMTG.

:) hello
Please HowManyToGo can you explain me how you gets the powerfor this equation thanks :
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 [#permalink] New post 28 Jun 2005, 09:19
Mandy,

147000 =147*1000 = 49 * 3 * 10^3= 7^2*3^1*5^3*2^3
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 [#permalink] New post 28 Jun 2005, 09:40
AJB77 wrote:
Mandy,

147000 =147*1000 = 49 * 3 * 10^3= 7^2*3^1*5^3*2^3


:) thanks AJB it is prime factorisation
  [#permalink] 28 Jun 2005, 09:40
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