pranav123 wrote:

Hello Friends,

I would like you to help me with coordinate geometry. This is a problem from MGMAT. The line is represented by equation y = x is the perpendicular bisector of line segment AB. If AB has the coordinates (-3,3), what are the coordinates of B?

I understand that the perpendicular bisector slope is 1 so the slope os segment AB is −1. so by substituting the values we get b.

y=mx+b

3=-1(-3)+b

0=b

line containing segment AB is y=-x

For these two lines

y=x———(1)

y=-x———(2)

so x=-x

then how to proceed?

how can we determine x=0 and y=0 and find midpoints.

The answer is B(3,-3)

Can you put some light?

Please explain step by step as my maths is pretty weak.

Thank you

From the equations, you can see that the line y=-x is bisected at the origin by y = x. So the midpoint of segment AB is (0,0).

Midpoint of a line segment having points

A(x_1,y_1) and B(x_2,y_2) is

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})We have the values of the point A and the midpoint. So point be can be easily found.

Kudos Please... If my post helped.

_________________

Did you find this post helpful?... Please let me know through the Kudos button.

Thanks To The Almighty - My GMAT Debrief

GMAT Reading Comprehension: 7 Most Common Passage Types