Find all School-related info fast with the new School-Specific MBA Forum

It is currently 24 May 2013, 23:25
Customize  |  Hide

The line represented by equation y=x is the perpendicular

  Question banks Downloads My Bookmarks Reviews  
Author Message
TAGS:
Intern
Intern
Joined: 18 Oct 2012
Posts: 4
Followers: 0

Kudos [?]: 4 [0], given: 9

The line represented by equation y=x is the perpendicular [#permalink] New post 27 Oct 2012, 20:28
00:00

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions
The line represented by equation y=x is the perpendicular bisector of line segment AB. If A has the coordinates (-3,3), what are the coordinates of B?

[Reveal] Spoiler:
Hello Friends,

I would like you to help me with coordinate geometry. This is a problem from MGMAT.


I understand that the perpendicular bisector slope is 1 so the slope os segment AB is −1. so by substituting the values we get b.
y=mx+b
3=-1(-3)+b
0=b
line containing segment AB is y=-x
For these two lines
y=x———(1)
y=-x———(2)
so x=-x
then how to proceed?
how can we determine x=0 and y=0 and find midpoints.

The answer is B(3,-3)
Can you put some light?
Please explain step by step as my maths is pretty weak.
Thank you

Last edited by Bunuel on 29 Oct 2012, 06:51, edited 1 time in total.
Renamed the topic, edited the question and moved to PS forum.
Manhattan GMAT Discount CodesKaplan GMAT Prep Discount CodesVeritas Prep GMAT Discount Codes
1 KUDOS received
Director
Director
User avatar
Joined: 02 Jul 2012
Posts: 767
Location: India
Concentration: Strategy
GMAT 1: 740 Q49 V42
GPA: 3.8
WE: Engineering (Energy and Utilities)
Followers: 19

Kudos [?]: 260 [1] , given: 45

GMAT Tests User
Re: coordinate geometry [#permalink] New post 27 Oct 2012, 23:24
1
This post received
KUDOS
pranav123 wrote:
Hello Friends,
I would like you to help me with coordinate geometry. This is a problem from MGMAT. The line is represented by equation y = x is the perpendicular bisector of line segment AB. If AB has the coordinates (-3,3), what are the coordinates of B?

I understand that the perpendicular bisector slope is 1 so the slope os segment AB is −1. so by substituting the values we get b.
y=mx+b
3=-1(-3)+b
0=b
line containing segment AB is y=-x
For these two lines
y=x———(1)
y=-x———(2)
so x=-x
then how to proceed?
how can we determine x=0 and y=0 and find midpoints.

The answer is B(3,-3)
Can you put some light?
Please explain step by step as my maths is pretty weak.
Thank you


From the equations, you can see that the line y=-x is bisected at the origin by y = x. So the midpoint of segment AB is (0,0).

Midpoint of a line segment having points A(x_1,y_1) and B(x_2,y_2) is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We have the values of the point A and the midpoint. So point be can be easily found.

Kudos Please... If my post helped.
_________________

Kudos Please... If my post helped.

Thanks To The Almighty - My GMAT Debrief
My Own CR Question 1|My Own CR Question 2|My Own DS Question 1|My Own DS Question 2|
My Own PS Question 1

1 KUDOS received
GMAT Club team member
User avatar
Joined: 02 Sep 2009
Posts: 11611
Followers: 1802

Kudos [?]: 9600 [1] , given: 829

Re: The line represented by equation y=x is the perpendicular [#permalink] New post 29 Oct 2012, 06:54
1
This post received
KUDOS
pranav123 wrote:
The line represented by equation y=x is the perpendicular bisector of line segment AB. If A has the coordinates (-3,3), what are the coordinates of B?

[Reveal] Spoiler:
Hello Friends,

I would like you to help me with coordinate geometry. This is a problem from MGMAT.


I understand that the perpendicular bisector slope is 1 so the slope os segment AB is −1. so by substituting the values we get b.
y=mx+b
3=-1(-3)+b
0=b
line containing segment AB is y=-x
For these two lines
y=x———(1)
y=-x———(2)
so x=-x
then how to proceed?
how can we determine x=0 and y=0 and find midpoints.

The answer is B(3,-3)
Can you put some light?
Please explain step by step as my maths is pretty weak.
Thank you


Similar questions to practice:
in-the-rectangular-coordinate-system-above-the-line-y-x-129932.html
in-the-rectangular-coordinate-system-the-line-y-x-is-the-132646.html
the-line-represented-by-the-equation-y-4-2x-is-the-127770.html

ALSO, PLEASE READ CAREFULLY AND FOLLOW: rules-for-posting-please-read-this-before-posting-133935.html
_________________

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!


What are GMAT Club Tests?
25 extra-hard Quant Tests

Find out what's new at GMAT Club - latest features and updates

Re: The line represented by equation y=x is the perpendicular   [#permalink] 29 Oct 2012, 06:54
    Similar topics Author Replies Last post
Similar
Topics:
New posts What is the equation of the line that is perpendicular to mitul 2 29 Oct 2006, 20:16
New posts What is the equation of the line that is perpendicular to bmwhype2 2 21 Nov 2007, 06:28
New posts What is the equation of the line that is perpendicular to arjtryarjtry 7 02 Sep 2008, 02:42
New posts What is the equation of the line that is perpendicular to tkarthi4u 3 01 Oct 2009, 08:25
New posts EXPERTS_POSTS_IN_THIS_TOPIC What is the equation of a line perpendicular to lines Archit143 7 11 Nov 2012, 15:52
Display posts from previous: Sort by

The line represented by equation y=x is the perpendicular

  Question banks Downloads My Bookmarks Reviews  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.