Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A) Insuff. It can be (-12, -12, 0 , 12, 12) or (-4, -6, -14, 1,23) ...
B) Insuff. Similar to above...

If there are equal positive and negative values, |mean| of each would be same. From A and B, it can be inferred it is not the case.
if |mean of positive| > |mean of negative|
The |value per positive| is more. Which means fewer positive numbers than negative.
So from Above, the answer to the question is 'No'.

Re: Above Average Averages Question [#permalink]
16 Oct 2005, 09:40

gsr wrote:

HIMALAYA wrote:

suppose if negative numbers = 3, positive numbers = 2 suppose if negative numbers = 4, positive numbers = 1 in both of the conditions, we cannot have a mean 0.

1. (-6,-7,-8,10,11) -> mean is 0 2. (-6,-7,-8,-10,31) -> mean is 0

that is not the solution. donot forget the constraints given in statement i and ii.

If the constraint also said "all numbers in the sequence are integers", then what you say is true (N=4,P=1 or N=3,P=2) and maybe, we can say question/answer is impossible, forget A or B or....

Any one possibility is enough. Like this one -> (-6, -6, 0, 0, 12)

If the constraint also said "all numbers in the sequence are integers", then what you say is true (N=4,P=1 or N=3,P=2) and maybe, we can say question/answer is impossible, forget A or B or....

Any one possibility is enough. Like this one -> (-6, -6, 0, 0, 12)

no, its not possible and your example is flawed because 0 is not positive and the mean of 0, 0 and 12 is also not 12..

still do not forget the constraints gievn in statements 1 and 2.

Quote:

The mean value of 5 numbers is 0. Are there more positive than negative values in this group of numbers?

1) The mean of positive numbers in the group is 12 2) The mean of negative numbers in the group is -6

I submitted my Cambridge MBA application in on time. But do have to say I took a laziez faire approach to the whole submission thing. Even went to the...

For my Cambridge essay I have to write down by short and long term career objectives as a part of the personal statement. Easy enough I said, done it...