The mean value of 5 numbers is 0. Are there more positive : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 16 Jan 2017, 17:47

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# The mean value of 5 numbers is 0. Are there more positive

Author Message
Director
Joined: 14 Oct 2003
Posts: 587
Location: On Vacation at My Crawford, Texas Ranch
Followers: 1

Kudos [?]: 48 [0], given: 0

The mean value of 5 numbers is 0. Are there more positive [#permalink]

### Show Tags

16 Oct 2005, 08:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The mean value of 5 numbers is 0. Are there more positive than negative values in this group of numbers?

1) The mean of positive numbers in the group is 12

2) The mean of negative numbers in the group is -6
Director
Joined: 21 Aug 2005
Posts: 793
Followers: 2

Kudos [?]: 24 [0], given: 0

### Show Tags

16 Oct 2005, 08:52
C

A) Insuff. It can be (-12, -12, 0 , 12, 12) or (-4, -6, -14, 1,23) ...
B) Insuff. Similar to above...

If there are equal positive and negative values, |mean| of each would be same. From A and B, it can be inferred it is not the case.
if |mean of positive| > |mean of negative|
The |value per positive| is more. Which means fewer positive numbers than negative.
So from Above, the answer to the question is 'No'.
SVP
Joined: 05 Apr 2005
Posts: 1731
Followers: 5

Kudos [?]: 74 [0], given: 0

Re: Above Average Averages Question [#permalink]

### Show Tags

16 Oct 2005, 09:17
C should be the answer. but can we make a question like this one?

from the question stem and information provided, there are more negative numbers. how do we make a question subject to the information provided above?

suppose if negative numbers = 3, positive numbers = 2
suppose if negative numbers = 4, positive numbers = 1

in both of the conditions, we cannot have a mean 0.
Director
Joined: 21 Aug 2005
Posts: 793
Followers: 2

Kudos [?]: 24 [0], given: 0

Re: Above Average Averages Question [#permalink]

### Show Tags

16 Oct 2005, 09:25
HIMALAYA wrote:
suppose if negative numbers = 3, positive numbers = 2
suppose if negative numbers = 4, positive numbers = 1

in both of the conditions, we cannot have a mean 0.

1. (-6,-7,-8,10,11) -> mean is 0
2. (-6,-7,-8,-10,31) -> mean is 0
SVP
Joined: 05 Apr 2005
Posts: 1731
Followers: 5

Kudos [?]: 74 [0], given: 0

Re: Above Average Averages Question [#permalink]

### Show Tags

16 Oct 2005, 09:40
gsr wrote:
HIMALAYA wrote:
suppose if negative numbers = 3, positive numbers = 2
suppose if negative numbers = 4, positive numbers = 1
in both of the conditions, we cannot have a mean 0.

1. (-6,-7,-8,10,11) -> mean is 0
2. (-6,-7,-8,-10,31) -> mean is 0

that is not the solution. donot forget the constraints given in statement i and ii.
Director
Joined: 21 Aug 2005
Posts: 793
Followers: 2

Kudos [?]: 24 [0], given: 0

### Show Tags

16 Oct 2005, 10:13

If the constraint also said "all numbers in the sequence are integers", then what you say is true (N=4,P=1 or N=3,P=2) and maybe, we can say question/answer is impossible, forget A or B or....

Any one possibility is enough. Like this one -> (-6, -6, 0, 0, 12)
SVP
Joined: 05 Apr 2005
Posts: 1731
Followers: 5

Kudos [?]: 74 [0], given: 0

### Show Tags

16 Oct 2005, 10:33
gsr wrote:

If the constraint also said "all numbers in the sequence are integers", then what you say is true (N=4,P=1 or N=3,P=2) and maybe, we can say question/answer is impossible, forget A or B or....

Any one possibility is enough. Like this one -> (-6, -6, 0, 0, 12)

no, its not possible and your example is flawed because 0 is not positive and the mean of 0, 0 and 12 is also not 12..

still do not forget the constraints gievn in statements 1 and 2.
Quote:
The mean value of 5 numbers is 0. Are there more positive than negative values in this group of numbers?

1) The mean of positive numbers in the group is 12
2) The mean of negative numbers in the group is -6
Director
Joined: 14 Oct 2003
Posts: 587
Location: On Vacation at My Crawford, Texas Ranch
Followers: 1

Kudos [?]: 48 [0], given: 0

### Show Tags

16 Oct 2005, 12:29
OA is C good work fellow geeks
16 Oct 2005, 12:29
Display posts from previous: Sort by