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The Middlebury train station is between the Appleton and

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SVP
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The Middlebury train station is between the Appleton and [#permalink] New post 16 Aug 2008, 06:46
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A
B
C
D
E

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The Middlebury train station is between the Appleton and Lancaster stations and all three are serviced by the same track. What is the distance between Middlebury and Lancaster?

(1) If a train can travel 50 miles on one pound of coal, it will use twice as much coal traveling from MiddleBury to Lancaster as it will use to travel between Middlebury and Appleton.

(2) Traveling from Appleton to Middlebury at an average rate of 35 mph takes 30 minutes longer than at an average rate of 55 mph.



Please explain your answer and why the other answer choices are wrong.
thanks
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Re: DS: Distance [#permalink] New post 16 Aug 2008, 06:58
tarek99 wrote:
The Middlebury train station is between the Appleton and Lancaster stations and all three are serviced by the same track. What is the distance between Middlebury and Lancaster?

(1) If a train can travel 50 miles on one pound of coal, it will use twice as much coal traveling from MiddleBury to Lancaster as it will use to travel between Middlebury and Appleton.

(2) Traveling from Appleton to Middlebury at an average rate of 35 mph takes 30 minutes longer than at an average rate of 55 mph.

Please explain your answer and why the other answer choices are wrong.
thanks


statement 1 : AM = 2x and ML = x, AL = 3x... not suff
statement 2 : AM/35 - AM/55 = 0.5, we can find AM but we have to find ML ... not suff

combine : ML = AM/2 ... suff
C
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Re: DS: Distance [#permalink] New post 16 Aug 2008, 09:21
The Middlebury train station is between the Appleton and Lancaster stations and all three are serviced by the same track. What is the distance between Middlebury and Lancaster?

(1) If a train can travel 50 miles on one pound of coal, it will use twice as much coal traveling from MiddleBury to Lancaster as it will use to travel between Middlebury and Appleton.

(2) Traveling from Appleton to Middlebury at an average rate of 35 mph takes 30 minutes longer than at an average rate of 55 mph.
------------------------
(1) does not give nay info on the actual cost used. Insufficient. Not sufficient.

(2) we have no info about the distance between M and L. Not sufficient.

(1) + (2)
From (2), assume distance from A to M is D
D = 35(t + 0.5) = 55(t)
35t + 35/2 = 55t
20t = 35/2
t=35/40=7/8
D = 55 *(7/8)

From (1)
assume distance from M to L is E
E = 2D
E = 110*(7/8)

Sufficient

(C)
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Re: DS: Distance [#permalink] New post 16 Aug 2008, 12:56
OA is C. I chose B because I assumed that M is exactly in the middle. I guess when we are told that M is between the other 2 stations, that doesn't necessarily mean that it is exactly in the middle, but rather anywhere between the 2 stations. cool so i know where i made my mistake.
thanks guys
Re: DS: Distance   [#permalink] 16 Aug 2008, 12:56
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