Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
02 Dec 2009, 19:34
10
This post was BOOKMARKED
00:00
A
B
C
D
E
Difficulty:
85% (hard)
Question Stats:
51% (02:51) correct
49% (01:44) wrong based on 446 sessions
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
A. 2 feet per second B. 2.5 feet per second C. 3 feet per second D. 4 feet per second E. 5 feet per second
Re: Question from Manhattan CAT [#permalink]
02 Dec 2009, 22:35
1
This post received KUDOS
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
3.75feet per second?
total distance is 300 feets 120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec
so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
Re: Question from Manhattan CAT [#permalink]
03 Dec 2009, 01:11
9
This post received KUDOS
1
This post was BOOKMARKED
Here's what I think the answer should be -------
Time Bill takes to catchup with group = 120/3 = 40 secs Time Group has moved in 40 secs = 40 x 3 = 120 feet Remaining Distance on walkway = 300 - 120 -120 = 60 Time taken to cover the last 60 ft = 60/3 = 20sec
Total time Bill spends on walkway = 40 + 20 = 60 secs Total length of walkway = 300 feet
Bill's Average speed = 300/60 = 5 ft/sec
Last edited by prome2 on 03 Dec 2009, 01:31, edited 1 time in total.
Re: Question from Manhattan CAT [#permalink]
03 Dec 2009, 01:25
1
This post received KUDOS
kp1811 wrote:
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
3.75feet per second?
total distance is 300 feets 120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec
so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
I could be wrong, but the average of 2 average speeds is not the average speed of the entire journey.
Let's take a man cycling 60 miles to work, at 10 miles/hour there and 15 miles/hour back. The average of the two average speeds will be 12.5 miles/hour
However, the computed average speed is total dist over total time. If he cycles 10 miles/hour there, he will take 6 hours, and at 15 miles/hour back he will take 4 hours.
120miles/10 hours = 12 miles/hour
----
Although I believe weighted average could be used to compute average speed. But you would need to know time travelled at each speed.
Re: Question from Manhattan CAT [#permalink]
03 Dec 2009, 03:40
kp1811 wrote:
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
3.75feet per second?
total distance is 300 feets 120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec
so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
my bad....the above is incorrect
120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec but in this 20sec the group moves a further of 20*3= 60feet so Bill will take another 60/6 =10sec to catch the group. Now remaining 120 feet will be covered in 120/3 = 40 sec. So total time to cover is 20+10+40 = 70sec Avg speed = 300/70 = 30/7 feet/sec
Re: Question from Manhattan CAT [#permalink]
03 Dec 2009, 07:14
prome2 wrote:
Here's what I think the answer should be -------
Time Bill takes to catchup with group = 120/3 = 40 secs Time Group has moved in 40 secs = 40 x 3 = 120 feet Remaining Distance on walkway = 300 - 120 -120 = 60 Time taken to cover the last 60 ft = 60/3 = 20sec
Total time Bill spends on walkway = 40 + 20 = 60 secs Total length of walkway = 300 feet
Bill's Average speed = 300/60 = 5 ft/sec
This is correct. Average speed is total distance/total time.
Re: Question from Manhattan CAT [#permalink]
07 May 2012, 01:06
kp1811 wrote:
kp1811 wrote:
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
3.75feet per second?
total distance is 300 feets 120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec
so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
my bad....the above is incorrect
120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec but in this 20sec the group moves a further of 20*3= 60feet so Bill will take another 60/6 =10sec to catch the group. Now remaining 120 feet will be covered in 120/3 = 40 sec. So total time to cover is 20+10+40 = 70sec Avg speed = 300/70 = 30/7 feet/sec
is this correct? does the group move further, even so is it required to be calculated for bill?
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
09 May 2012, 10:36
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
A. 2 feet per second B. 2.5 feet per second C. 3 feet per second D. 4 feet per second E. 5 feet per second
Hi Bunuel, could u please explain how to solve this question... Thanks in advance
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
30 May 2012, 18:24
9
This post received KUDOS
This is how I broke it down:
Total Distance = 300 feet default rate is 3fps (feet per second) walking rate is 6fps (default + walking) catch up rate: is walking rate - default rate = 6-3 = 3fps
Part 1: Time for Catch up As he gets on the walk way he instantly starts "catching up" to the group that is 120 feet ahead of him. How long does this take?
D/R = Time; so 120feet/3fps [ note I'm using the catch up rate here ] = 40 seconds of catch up
After 40 seconds, how much of the 300 feet of the moonwalk has been used? well if he was moving for 40 seconds at 6 feet per second (he was walking) then he covered 240 feet of actual walkway.
300-240 feet = 60 feet.
There are only 60 feet left of walkway.
Part 2: Standing with the crowd Now bill just idles with the crowd for the last 60 feet. 60ft/3fps [ note this is the default rate ] = 20 seconds.
Part 3: Average rate
6 fps for 40 seconds = 240 feet 3 fps for 20 seconds = 60 feet X fps for 60 seconds = 300 feet
300/60 = 5fps average rate. Answer is E. _________________
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
20 Sep 2013, 10:21
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
20 Sep 2013, 10:29
Expert's post
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
A. 2 feet per second B. 2.5 feet per second C. 3 feet per second D. 4 feet per second E. 5 feet per second
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
26 Sep 2013, 09:29
1
This post received KUDOS
I agree with the above posters about the way to handle the equations (Catona & Prome2) but to me there is an option that hasn't been discussed that just POPS out at me. I don't know if it does for anyone else...
If you look at the options for the choices:
A. 2 feet per second B. 2.5 feet per second C. 3 feet per second D. 4 feet per second E. 5 feet per second
A, B, and C don't make ANY sense! we know for some time...(a majority of the 300ft) Bill will walk at a pace of 6ft per second...and then at some later time he will stop and move at 3 ft per second... The average MUST be between 3-6 ft per second or the Earth is FLAT!!!.
So we are down to D & E, D doesn't make sense on a weighted averages level because we know when Bill gets on the walkway the patrons are already 40% of the way down the 300ft walkway AND they are still moving at half the rate of Bill!! So for Bill to average 4 ft per second he would have had to spend a majority of the 300 ft at 3ft per second because 4 is much closer (when you factor in the size of the values we're dealing with 2 is double 1) to 3 than to 6. We know from the information that isn't possible. Bill must have spent the majority of his time at 6 ft per second before he stopped walking. That leaves only answer E as plausible.
Re: Question from Manhattan CAT [#permalink]
22 Feb 2014, 01:20
prome2 wrote:
Here's what I think the answer should be -------
Time Bill takes to catchup with group = 120/3 = 40 secs Time Group has moved in 40 secs = 40 x 3 = 120 feet......Please make me understand whether bill there in this group to cover 120 feet....... Remaining Distance on walkway = 300 - 120 -120 = 60 Time taken to cover the last 60 ft = 60/3 = 20sec
Total time Bill spends on walkway = 40 + 20 = 60 secs Total length of walkway = 300 feet
Re: Question from Manhattan CAT [#permalink]
22 Feb 2014, 02:04
Expert's post
1
This post was BOOKMARKED
prasannajeet wrote:
prome2 wrote:
Here's what I think the answer should be -------
Time Bill takes to catchup with group = 120/3 = 40 secs Time Group has moved in 40 secs = 40 x 3 = 120 feet......Please make me understand whether bill there in this group to cover 120 feet....... Remaining Distance on walkway = 300 - 120 -120 = 60 Time taken to cover the last 60 ft = 60/3 = 20sec
Total time Bill spends on walkway = 40 + 20 = 60 secs Total length of walkway = 300 feet
Bill's Average speed = 300/60 = 5 ft/sec
I was little confused please som1 help me out
No, he is not. Bill takes 40 seconds to catch up the group but in that time the walkway continues to move at 3 feet per second, thus the group (as well as Bill) moves 3*40=120 feet towards the end.
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
27 Feb 2014, 13:00
Hello, I just bumped into this question, I solved it this way : At time t, Bill meets the crowd at the the distance x, the crowd has covered 120+X : => X/6=(X+120)/3 => X=720/3=240 feet (I neglected the sign '-', x being a distance, so an absolute value) So, Bill spends 240/6 =40 sec to cover the 240 feet
Remain 60 feet that bills covers in : 60/3 = 20 s
Hence total time : 40+20=60 sec.t
Bill s rate is : 300/60 = 5 feet
I think there s sthg wrong with my reasoning but I cant figure it out Thank you for helping
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
28 Feb 2014, 02:44
Expert's post
breakfree1 wrote:
Hello, I just bumped into this question, I solved it this way : At time t, Bill meets the crowd at the the distance x, the crowd has covered 120+X : => X/6=(X+120)/3 => X=720/3=240 feet (I neglected the sign '-', x being a distance, so an absolute value) So, Bill spends 240/6 =40 sec to cover the 240 feet
Remain 60 feet that bills covers in : 60/3 = 20 s
Hence total time : 40+20=60 sec.t
Bill s rate is : 300/60 = 5 feet
I think there s sthg wrong with my reasoning but I cant figure it out Thank you for helping
The equation should be \(\frac{x}{6}=\frac{(x-120)}{3}\) --> \(x=240\).
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
28 May 2015, 18:23
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: The ‘moving walkway’ is a 300-foot long walkway consisting [#permalink]
28 May 2015, 19:20
2
This post received KUDOS
Expert's post
Gmatter111 wrote:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
A. 2 feet per second B. 2.5 feet per second C. 3 feet per second D. 4 feet per second E. 5 feet per second
Using relative speed concepts:
Bill covers 120 feet at a relative speed of 6 - 3 = 3 feet/sec. Time taken to cover 120 feet = 120/3 = 40 sec Distance covered in 40 secs = 6*40 = 240 feet So now he just has 300 - 240 = 60 feet leftover to cover at 3 feet/sec Time taken to cover 60 feet = 60/3 = 20 sec
Average Speed = Total Distance/Total Time = 300/(40 + 20) = 5 feet/sec
As I’m halfway through my second year now, graduation is now rapidly approaching. I’ve neglected this blog in the last year, mainly because I felt I didn’...
Perhaps known best for its men’s basketball team – winners of five national championships, including last year’s – Duke University is also home to an elite full-time MBA...
Hilary Term has only started and we can feel the heat already. The two weeks have been packed with activities and submissions, giving a peek into what will follow...