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The music class consists of 4 girls and 7 boys. How many way

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The music class consists of 4 girls and 7 boys. How many way [#permalink] New post 16 Oct 2007, 10:50
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The music class consists of 4 girls and 7 boys. How many ways can a group of 3 be formed if it has to include at least one boy?

A. 155
B. 158
C. 161
D. 165
E. 172
[Reveal] Spoiler: OA

Last edited by Bunuel on 30 Jun 2012, 03:04, edited 1 time in total.
Edited the question.
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Re: PS Combinatorics - Music Class [#permalink] New post 16 Oct 2007, 11:02
bmwhype2 wrote:
The music class consists of 4 girls and 7 boys. How many ways can a group of 3 be formed if it has to include at least one boy?

155
158
161
165
172


Classic combination problem
At least 1 boy = Total - all girls
All girls = C(4,3) = 4
Total combination = C(11,3) = 165
Ans = 165-4 = 161
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 [#permalink] New post 16 Oct 2007, 11:11
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Case 1: All three boys
(7 choose 3) = 35

Case 2: Two boys, one girl
(7 choose 2) * (4 choose 1) = 84

Case 3: One boy, two girls
(7 choose 1) * (4 choose 2) = 42


Add them up 35 + 84 + 42 = 161
C
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Re: [#permalink] New post 29 Jun 2012, 12:47
jimjohn wrote:
Case 1: All three boys
(7 choose 3) = 35

Case 2: Two boys, one girl
(7 choose 2) * (4 choose 1) = 84

Case 3: One boy, two girls
(7 choose 1) * (4 choose 2) = 42


Add them up 35 + 84 + 42 = 161
C


I don't really understand how Case 2 and 3 above are calculated. Any help please?


Thanks,
Diana
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Re: Re: [#permalink] New post 30 Jun 2012, 03:03
Expert's post
dianamao wrote:
jimjohn wrote:
Case 1: All three boys
(7 choose 3) = 35

Case 2: Two boys, one girl
(7 choose 2) * (4 choose 1) = 84

Case 3: One boy, two girls
(7 choose 1) * (4 choose 2) = 42


Add them up 35 + 84 + 42 = 161
C


I don't really understand how Case 2 and 3 above are calculated. Any help please?


Thanks,
Diana


The music class consists of 4 girls and 7 boys. How many ways can a group of 3 be formed if it has to include at least one boy?
A. 155
B. 158
C. 161
D. 165
E. 172

Reverse Approach:

The # of groups with at least one boy equal to total groups of 3 that can be formed out of 11 people minus groups with all girls: C^3_{11}-C^3_4=161.

Answer: C.

Direct Approach:

The # of groups with at least one boy equal to groups with one boy (and 2 girls) plus groups with 2 boys (and 1 girl) plus groups with 3 boys: C^1_{7}*C^2_4+C^2_{7}*C^1_4+C^3_{7}=161.

Answer: C.
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Re: The music class consists of 4 girls and 7 boys. How many way [#permalink] New post 30 Jun 2012, 03:50
Awesome. Thanks Bunuel!

Cheers,
Diana
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Re: The music class consists of 4 girls and 7 boys. How many way [#permalink] New post 30 Dec 2013, 06:34
bmwhype2 wrote:
The music class consists of 4 girls and 7 boys. How many ways can a group of 3 be formed if it has to include at least one boy?

A. 155
B. 158
C. 161
D. 165
E. 172


Reverse combinatorics approach is preferred method on this one
Note that at least 1 boy gives clue to using this method

All combinations - four girls = answer

All combinations is 11C3 = 165

All girls 4C3 = 4

So our answer is 165-4 = 161

Hence, answer is (C)

Hope it helps
Cheers!

J :)
Re: The music class consists of 4 girls and 7 boys. How many way   [#permalink] 30 Dec 2013, 06:34
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