The number A is a two-digit positive integer; the number B is the two-digit positive integer formed by reversing the digits of A. if Q=10B-A, what is the value of Q?

(1) The tens digit of A is 7

(2) The tens digit of B is 6

I am able to get the value of Q using (1) which is contrary to the provided answer.

(1)

A = 7/10 + x

B = x/10 + 7

Q=10B-A

Q=10(x/10 + 7) - (7/10 + x)

Q= x + 70 - 7/10 - x

Q= 10x + 700 - 7 - 10x

Q= 700 - 7

Q= 693

Does this mean that the answer provided by Manhattan is wrong?

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