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The number of passengers on a certain bus at any given time

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Director
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The number of passengers on a certain bus at any given time [#permalink] New post 13 Sep 2008, 15:41
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0
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Re: another mgmat [#permalink] New post 13 Sep 2008, 15:49
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0


The correct formula is P = -2(S – 4)^2 + 32
Director
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Re: another mgmat [#permalink] New post 13 Sep 2008, 15:54
C

the max number of passenger is at the 4th stop, at the 6th stop, there will be 24
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Re: another mgmat [#permalink] New post 13 Sep 2008, 16:01
If by 2(S – 4)2 + 32 you mean 2(S – 4)^2 + 32 .. then yes after 6 stops , the number of passenger will be 24

IMO C .
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Re: another mgmat [#permalink] New post 13 Sep 2008, 16:14
(C) for me too.

Based on the formula, highest # of passenger is when s=4, i.e P=32.
2 stops after when s=4 is -> s=6. P=24 when S=6 and hence (C)
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Re: another mgmat [#permalink] New post 13 Sep 2008, 17:00
OA is C, sorry about the typo
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Re: another mgmat [#permalink] New post 13 Sep 2008, 22:45
gmatnub wrote:
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0


The correct formula is P = -2(S – 4)^2 + 32


IMO C
4th stop max=32 ,
6th stop => 24 => IMO C
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Re: another mgmat [#permalink] New post 14 Sep 2008, 23:42
gmatnub wrote:
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0


The correct formula is P = -2(S – 4)^2 + 32



That made sense. Otherwise, with S = 0, P was not coming out to 0.
Re: another mgmat   [#permalink] 14 Sep 2008, 23:42
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