Find all School-related info fast with the new School-Specific MBA Forum

It is currently 29 Aug 2015, 15:33
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

The numbers x and y are three-digit positive integers, and x

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Manager
Manager
avatar
Joined: 10 Oct 2005
Posts: 114
Location: Hollywood
Followers: 0

Kudos [?]: 22 [0], given: 0

The numbers x and y are three-digit positive integers, and x [#permalink] New post 12 May 2006, 10:55
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 0 sessions
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x < y, which of the following must be true?


I. The units digit of x + y is greater than the units digit of either x or y.
II. The tens digit of x + y equals 2.
III. The hundreds digit of y is at least 5.


A. II only
B. III only
C. I and II
D. I and III
E. II and III
_________________

The GMAT, too tough to be denied.
Beat the tough questions...

Intern
Intern
User avatar
Joined: 04 May 2006
Posts: 49
Followers: 0

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 12 May 2006, 11:54
Think its B. (3 only)
1.Then Unit's digit can be 5 & 6, still all the conditions are fulfilled. So its not always true.
2.The sum of units digit may give carry so sum of tens digit may give 3.
3.Since we're given that y > x and addition of these numbers generate the carry, y has to be atleast 5.
_________________

If A equals success, then the formula is: A = X + Y + Z, X is work. Y is play. Z is keep your mouth shut.
Albert Einstein

VP
VP
avatar
Joined: 21 Sep 2003
Posts: 1065
Location: USA
Followers: 3

Kudos [?]: 43 [0], given: 0

 [#permalink] New post 12 May 2006, 11:59
(B) III only.

I --> May or may not be true. Take 377 + 855 = 1232. Not true.
II --> May or may not be true. Same eg as above.

III-> Given x<y and x+y = 4-digit integer, let the numbers be of the form

Quote:
a7b --> x
c5d --> y
-----
efgh
-----

f = a+c+1 >= 10
=> a+c > = 9
since x <y, a <= c Hence the least value that "c" can have is 5.
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

Senior Manager
Senior Manager
User avatar
Joined: 08 Jun 2004
Posts: 498
Location: Europe
Followers: 1

Kudos [?]: 27 [0], given: 0

 [#permalink] New post 12 May 2006, 22:18
III only is th answer.

given x<y,
x = .7.
y = .5.

I. The units digit of x + y is greater than the units digit of either x or y.
Not sufficient as x could be equal 479 and y = 551, so x+y= 1030 or
x could be equal 473 and y = 553, so x+y= 1026.

II. The tens digit of x + y equals 2.
Not sufficient as tens digit can be equal 2 or 3, depends on units digits.

III. The hundreds digit of y is at least 5.
Sufficient information as y>x.
Director
Director
avatar
Joined: 16 Aug 2005
Posts: 946
Location: France
Followers: 1

Kudos [?]: 13 [0], given: 0

 [#permalink] New post 13 May 2006, 06:57
Let x = 470 and y = 650, x+y = 1120

I. This is not true from our example above.
II. This is always true.
III. In our example above it is surely true. But lets explore this one:

If x < y and x+y => 1000, then y must be at least 501.
Hence this is true as well.

So answer is E
Director
Director
avatar
Joined: 16 Aug 2005
Posts: 946
Location: France
Followers: 1

Kudos [?]: 13 [0], given: 0

 [#permalink] New post 13 May 2006, 06:59
M8 wrote:
III only is th answer.

given x<y,
x = .7.
y = .5.

I. The units digit of x + y is greater than the units digit of either x or y.
Not sufficient as x could be equal 479 and y = 551, so x+y= 1030 or
x could be equal 473 and y = 553, so x+y= 1026.

II. The tens digit of x + y equals 2.
Not sufficient as tens digit can be equal 2 or 3, depends on units digits.

III. The hundreds digit of y is at least 5.
Sufficient information as y>x.


M8- you said - "Not sufficient as tens digit can be equal 2 or 3, depends on units digits."

Thats a great catch, for which I was careless.

The correct answer in that case will be III only.
  [#permalink] 13 May 2006, 06:59
Display posts from previous: Sort by

The numbers x and y are three-digit positive integers, and x

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.