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The numbers x and y are three-digit positive integers, and x [#permalink]
 07 Oct 2008, 09:09
The numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x < y, which of the following must be true?
I. The units digit of x + y is greater than the units digit of either x or y.
II. The tens digit of x + y equals 2.
III. The hundreds digit of y is at least 5.
A. II only
B. III only
C. I and II
D. I and III
E. II and III
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Manager
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looks like D is the answer
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Lets assume x=470 and y=550 which satisfies the given conditions. Based on the three choices given, only III seems to make sense which is B. Please let me know if find it wrong anywhere.
thanks
SM
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you are right. the answer is B
after giving it a thought again, the first 2 statements will not make any difference in arriving at a four digit number.
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