Bumping for review and further discussion*. Get a kudos point for an alternative
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Well originally, i got this question wrong.
Bu then i figured an alternative approach which would have been very easy to start with, please let me know if there is something wrong with it.
First of all to look at the options, everything looks to be in the form of either,
a@(b@c) or (a@b)@c
Now lets quickly try to see the diff between the magnitude of these different forms, lets take a,b,c = 2 for comparison purpose.
2@(2@2) = 2@4 = 2^(2^(2^2)) = 2^16
while, (2@2)@2 = (2^2)@2 = 4@2 = 4^4 = 2^8
So well, there is a huge magnitude diff between the post, and option 1 def has much more wightage.
now, lets late at our options in the question : (all the options have either 2 or 3 as the values for a, b and c in a@(b@c) and (a@b)@c, so we can make a direct comparison.
We have B and D in a@(b@c) form, however since B has 1 as one of the numbers ( 1 and 0 are special no's with special properties),
so we can easily see that 3@(1@3) = 3@1 = 3 (which is most definitely the smallest)
Which leaves to D (2@16) now which is the answer.
PS: Like my approach? Please Help me with some Kudos.