The participants in a race consisted of 3 teams with 3 runners on each

Ans will be A

STmt 1: points to be awarded are 1,2,3,4,5, ie, total of 15 points. This stmt says that no team won more than 6, So 2 teams can get max of 6 points, and still we will have 3 points left which must have gone to third team. Sufficient.

Stmt 2: No two teammates finished in consecutive places, ie, no two team members got consecutive points.
It can be that Team A got 1,3, and 5 points, and B got 2 and 4 points and C got nothing.
It can also be that A, B and C got 1,2 and 3 points respectively. So stmt 2 is insufficient.

There is a risk of carrying over information given in option 1 while solving option 2. like i did, and concluded that B is sufficient !

here is how I did it.

1-2-3-4-5

if you take A while solving B, you think oh 1-3 * 2-4 * so 5th can be taken by thrid team. but there is no restriction if you take B alone, so it could be 1-3-5 and 2-4

I have to be careful

1-
There are 5 points to be given.
1st place 5
2nd place 4
3rd place 3
4th place 2 and
5th place 1 points.
Total it makes 15 points.
If no teams awarded greater than 6 points. Than in the worst case, two teams got 6 points. That makes at least 3 points given to the least awarded game. ( 6 + 6 + 3 = 15 )
Sufficient
2-
There is no certainty
say the ranking like.
1-team 1
2-team 2
3-team 1
4-team 2
5-team 1
Then team3 gets 0.
say the ranking like.
1-team 1
2-team 2
3-team 1
4-team 2
5-team 3
Then team3 gets 1.
Soooo, it is insufficient.

Answer is A.

The participants in a race consisted of 3 teams with 3 runners on each team. A team was awarded 6 –n points if one of its runners finished in nth place, where 1 <= n <= 5. If all of the runners finished the race and if there were no ties, was each team awarded at least one point?
(1) No team was awarded more than a total of 6 points.
(2) No pair of teammates finished in consecutive places among the top five places.

maximize the points for each team

team one

5 = first,4 secound,3 3rd,2 4th and 1 5th

from 1

team 1 maximum = 5+1 = 6
team 2 max = 4+2 = 6

team 3 = 3

then A is suff

from 2

insuff and insignificant

A

Highest point that can be awarded: 6-1 = 5
Lowest point that can be awarded: 6-5 = 1

Sum of all the points: 5+4+3+2+1= 15

Statement-1: No team got more than 6 points
Now even if two teams got 6 points each, 3 points will be left with third team.
Thus sufficient

Statement-2 No pair of team mate finished consecutive
Members can finish in following manner (For teams A,B,C)
ABABA BCCC or ABCABCABC or any other pattern
So not sufficient!

Hence A

Hi

I interpreted the question in a diff way

It says that there a 3 team and 3 runners in each team. So in all 9 runners

Now the scoring techniques

points = 6-n and 1<= n<=5

So i interpreted it as out of the 9 runner completing the exam only the first 5 would be scored and rest would get 0

So for statement 2 where we have that no two team member secure consecutive position then the worst score can be

9th postion- o
7th position - 0
5th position- 1
So atleast 1 point

Hence,sufficient

and the answer should be D.

Can anyone pls clarify this. Am I not understanding the question well.

You are right almost till the end but you missed one point.

Note this:
(2) No pair of teammates finished in consecutive places among the top five places

So they could have been in consecutive places in the last 3 spots - 9th, 8th and 7th - and the team would have got a total of 0 points in that case.

5,4,3,2,1

(1) must distribute above points among 3 teams to be true
Sufficient

(2) 5,3,1 and 4,2 and no points
5,3 and 4,2 and 1
Insufficient

Answer A

1st place = 6-1 = 5 points
2nd place = 6-2 = 4 points
3rd place = 6-3 = 3 points
4th place = 6-4 = 2 points
5th place = 6-5 = 1 point
Total = 5+4+3+2+1 = 15 points.

Statement 1:
Max for 2 teams = 2*6=12.
So 3rd team must get 15 - 12= 3 points.
So every team gets at least 1 point. Sufficient.

Statement 2:
Team A could be 1st, 3rd, 5th
Team B could be 2nd, 4th.
Only 2 teams get at least one point.

Team A could be 1st, 3rd, 5th.
Team B could be 2nd.
Team C could be 4th.
All 3 teams get at least 1 point.

Insufficient.

The correct answer is A.

Posted from my mobile device

OFFICIAL GMAT EXPLANATION

The problem indicates that 5 points were awarded for first place, 4 points for second place, 3 points for third place, 2 points for fourth place, and 1 point for fifth place, for a total of 15 points. Statement (1) indicates that no team was awarded more than 6 points. Suppose that two teams got the maximum of 6 points each, accounting for a total of 12 of the 15 points. Clearly, the third team would have gotten the other 3 points. Therefore, the answer must be A or D. Statement (2) is not conclusive. If no pair of teammates finished in consecutive order, then no team was awarded consecutive numbers of points. From this information alone, one team could have received (5 + 3 + 1) points and a second team (2 + 4) points, leaving no points for the third team; alternatively, one team could have received (5 + 2) points, a second team (3 + 1) points, leaving 4 points for the third team, etc. The best answer is A.

1st place = 6-1 = 5 points
2nd place = 6-2 = 4 points
3rd place = 6-3 = 3 points
4th place = 6-4 = 2 points
5th place = 6-5 = 1 point
Total number of points = 5+4+3+2+1 = 15

Statement 1:
Maximum number of points for 2 teams = 2*6 = 12, with the result that the number of points for the 3rd team = 15-12 = 3
Implication:
Every team must get at least 1 point.
SUFFICIENT.

Statement 2:
Case 1:
Team A could be 1st, 3rd, 5th.
Team B could be 2nd, 4th.
Here, only 2 teams get at least one point.

Case 2:
Team A could be 1st, 3rd, 5th.
Team B could be 2nd.
Team C could be 4th.
Here, all 3 teams get at least 1 point.
INSUFFICIENT.


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