The point (x,0) is equidistant to the points (1,-3) and : PS Archive
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The point (x,0) is equidistant to the points (1,-3) and

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Joined: 08 Aug 2005
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Kudos [?]: 49 [0], given: 0

The point (x,0) is equidistant to the points (1,-3) and [#permalink]

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06 May 2006, 04:06
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The point (x,0) is equidistant to the points (1,-3) and (8,4) , x=?

A 0.5
B 1
C 4
D 4.5
E 5
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Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 8 [0], given: 0

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06 May 2006, 04:14
Ans 5

(x-1) ^2 + (0 -(-3))^2 = (x-8) ^2 + (4-0) ^2

solve above and x =5
06 May 2006, 04:14
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